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[/] [openrisc/] [trunk/] [gnu-dev/] [or1k-gcc/] [libquadmath/] [math/] [expm1q.c] - Blame information for rev 864

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1 740 jeremybenn
/*                                                      expm1l.c
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 *
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 *      Exponential function, minus 1
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 *      128-bit __float128 precision
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 *
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 *
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 *
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 * SYNOPSIS:
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 *
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 * __float128 x, y, expm1l();
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 *
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 * y = expm1l( x );
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 *
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 *
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 *
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 * DESCRIPTION:
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 *
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 * Returns e (2.71828...) raised to the x power, minus one.
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 *
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 * Range reduction is accomplished by separating the argument
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 * into an integer k and fraction f such that
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 *
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 *     x    k  f
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 *    e  = 2  e.
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 *
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 * An expansion x + .5 x^2 + x^3 R(x) approximates exp(f) - 1
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 * in the basic range [-0.5 ln 2, 0.5 ln 2].
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 *
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 *
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 * ACCURACY:
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 *
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 *                      Relative error:
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 * arithmetic   domain     # trials      peak         rms
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 *    IEEE    -79,+MAXLOG    100,000     1.7e-34     4.5e-35
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 *
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 */
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/* Copyright 2001 by Stephen L. Moshier
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    This library is free software; you can redistribute it and/or
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    modify it under the terms of the GNU Lesser General Public
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    License as published by the Free Software Foundation; either
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    version 2.1 of the License, or (at your option) any later version.
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    This library is distributed in the hope that it will be useful,
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    but WITHOUT ANY WARRANTY; without even the implied warranty of
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    MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
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    Lesser General Public License for more details.
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    You should have received a copy of the GNU Lesser General Public
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    License along with this library; if not, write to the Free Software
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    Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307  USA */
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#include "quadmath-imp.h"
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/* exp(x) - 1 = x + 0.5 x^2 + x^3 P(x)/Q(x)
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   -.5 ln 2  <  x  <  .5 ln 2
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   Theoretical peak relative error = 8.1e-36  */
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static const __float128
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  P0 = 2.943520915569954073888921213330863757240E8Q,
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  P1 = -5.722847283900608941516165725053359168840E7Q,
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  P2 = 8.944630806357575461578107295909719817253E6Q,
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  P3 = -7.212432713558031519943281748462837065308E5Q,
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  P4 = 4.578962475841642634225390068461943438441E4Q,
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  P5 = -1.716772506388927649032068540558788106762E3Q,
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  P6 = 4.401308817383362136048032038528753151144E1Q,
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  P7 = -4.888737542888633647784737721812546636240E-1Q,
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  Q0 = 1.766112549341972444333352727998584753865E9Q,
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  Q1 = -7.848989743695296475743081255027098295771E8Q,
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  Q2 = 1.615869009634292424463780387327037251069E8Q,
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  Q3 = -2.019684072836541751428967854947019415698E7Q,
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  Q4 = 1.682912729190313538934190635536631941751E6Q,
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  Q5 = -9.615511549171441430850103489315371768998E4Q,
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  Q6 = 3.697714952261803935521187272204485251835E3Q,
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  Q7 = -8.802340681794263968892934703309274564037E1Q,
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  /* Q8 = 1.000000000000000000000000000000000000000E0 */
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/* C1 + C2 = ln 2 */
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  C1 = 6.93145751953125E-1Q,
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  C2 = 1.428606820309417232121458176568075500134E-6Q,
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/* ln (2^16384 * (1 - 2^-113)) */
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  maxlog = 1.1356523406294143949491931077970764891253E4Q,
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/* ln 2^-114 */
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  minarg = -7.9018778583833765273564461846232128760607E1Q;
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__float128
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expm1q (__float128 x)
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{
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  __float128 px, qx, xx;
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  int32_t ix, sign;
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  ieee854_float128 u;
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  int k;
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  /* Detect infinity and NaN.  */
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  u.value = x;
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  ix = u.words32.w0;
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  sign = ix & 0x80000000;
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  ix &= 0x7fffffff;
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  if (ix >= 0x7fff0000)
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    {
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      /* Infinity. */
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      if (((ix & 0xffff) | u.words32.w1 | u.words32.w2 | u.words32.w3) == 0)
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        {
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          if (sign)
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            return -1.0Q;
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          else
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            return x;
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        }
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      /* NaN. No invalid exception. */
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      return x;
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    }
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  /* expm1(+- 0) = +- 0.  */
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  if ((ix == 0) && (u.words32.w1 | u.words32.w2 | u.words32.w3) == 0)
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    return x;
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  /* Overflow.  */
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  if (x > maxlog)
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    return (HUGE_VALQ * HUGE_VALQ);
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  /* Minimum value.  */
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  if (x < minarg)
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    return (4.0/HUGE_VALQ - 1.0Q);
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  /* Express x = ln 2 (k + remainder), remainder not exceeding 1/2. */
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  xx = C1 + C2;                 /* ln 2. */
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  px = floorq (0.5 + x / xx);
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  k = px;
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  /* remainder times ln 2 */
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  x -= px * C1;
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  x -= px * C2;
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  /* Approximate exp(remainder ln 2).  */
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  px = (((((((P7 * x
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              + P6) * x
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             + P5) * x + P4) * x + P3) * x + P2) * x + P1) * x + P0) * x;
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  qx = (((((((x
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              + Q7) * x
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             + Q6) * x + Q5) * x + Q4) * x + Q3) * x + Q2) * x + Q1) * x + Q0;
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  xx = x * x;
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  qx = x + (0.5 * xx + xx * px / qx);
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  /* exp(x) = exp(k ln 2) exp(remainder ln 2) = 2^k exp(remainder ln 2).
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  We have qx = exp(remainder ln 2) - 1, so
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  exp(x) - 1 = 2^k (qx + 1) - 1
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             = 2^k qx + 2^k - 1.  */
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  px = ldexpq (1.0Q, k);
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  x = px * qx + (px - 1.0);
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  return x;
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}

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