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[/] [openrisc/] [trunk/] [gnu-old/] [gdb-6.8/] [intl/] [plural.y] - Blame information for rev 851

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1 24 jeremybenn
%{
2
/* Expression parsing for plural form selection.
3
   Copyright (C) 2000, 2001 Free Software Foundation, Inc.
4
   Written by Ulrich Drepper , 2000.
5
 
6
   This program is free software; you can redistribute it and/or modify it
7
   under the terms of the GNU Library General Public License as published
8
   by the Free Software Foundation; either version 2, or (at your option)
9
   any later version.
10
 
11
   This program is distributed in the hope that it will be useful,
12
   but WITHOUT ANY WARRANTY; without even the implied warranty of
13
   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
14
   Library General Public License for more details.
15
 
16
   You should have received a copy of the GNU Library General Public
17
   License along with this program; if not, write to the Free Software
18
   Foundation, Inc., 51 Franklin Street - Fifth Floor, Boston, MA 02110-1301,
19
   USA.  */
20
 
21
/* The bison generated parser uses alloca.  AIX 3 forces us to put this
22
   declaration at the beginning of the file.  The declaration in bison's
23
   skeleton file comes too late.  This must come before 
24
   because  may include arbitrary system headers.  */
25
#if defined _AIX && !defined __GNUC__
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 #pragma alloca
27
#endif
28
 
29
#ifdef HAVE_CONFIG_H
30
# include 
31
#endif
32
 
33
#include 
34
#include 
35
#include "plural-exp.h"
36
 
37
/* The main function generated by the parser is called __gettextparse,
38
   but we want it to be called PLURAL_PARSE.  */
39
#ifndef _LIBC
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# define __gettextparse PLURAL_PARSE
41
#endif
42
 
43
#define YYLEX_PARAM     &((struct parse_args *) arg)->cp
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#define YYPARSE_PARAM   arg
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%}
46
%pure_parser
47
%expect 7
48
 
49
%union {
50
  unsigned long int num;
51
  enum operator op;
52
  struct expression *exp;
53
}
54
 
55
%{
56
/* Prototypes for local functions.  */
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static struct expression *new_exp PARAMS ((int nargs, enum operator op,
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                                           struct expression * const *args));
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static inline struct expression *new_exp_0 PARAMS ((enum operator op));
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static inline struct expression *new_exp_1 PARAMS ((enum operator op,
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                                                   struct expression *right));
62
static struct expression *new_exp_2 PARAMS ((enum operator op,
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                                             struct expression *left,
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                                             struct expression *right));
65
static inline struct expression *new_exp_3 PARAMS ((enum operator op,
66
                                                   struct expression *bexp,
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                                                   struct expression *tbranch,
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                                                   struct expression *fbranch));
69
static int yylex PARAMS ((YYSTYPE *lval, const char **pexp));
70
static void yyerror PARAMS ((const char *str));
71
 
72
/* Allocation of expressions.  */
73
 
74
static struct expression *
75
new_exp (nargs, op, args)
76
     int nargs;
77
     enum operator op;
78
     struct expression * const *args;
79
{
80
  int i;
81
  struct expression *newp;
82
 
83
  /* If any of the argument could not be malloc'ed, just return NULL.  */
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  for (i = nargs - 1; i >= 0; i--)
85
    if (args[i] == NULL)
86
      goto fail;
87
 
88
  /* Allocate a new expression.  */
89
  newp = (struct expression *) malloc (sizeof (*newp));
90
  if (newp != NULL)
91
    {
92
      newp->nargs = nargs;
93
      newp->operation = op;
94
      for (i = nargs - 1; i >= 0; i--)
95
        newp->val.args[i] = args[i];
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      return newp;
97
    }
98
 
99
 fail:
100
  for (i = nargs - 1; i >= 0; i--)
101
    FREE_EXPRESSION (args[i]);
102
 
103
  return NULL;
104
}
105
 
106
static inline struct expression *
107
new_exp_0 (op)
108
     enum operator op;
109
{
110
  return new_exp (0, op, NULL);
111
}
112
 
113
static inline struct expression *
114
new_exp_1 (op, right)
115
     enum operator op;
116
     struct expression *right;
117
{
118
  struct expression *args[1];
119
 
120
  args[0] = right;
121
  return new_exp (1, op, args);
122
}
123
 
124
static struct expression *
125
new_exp_2 (op, left, right)
126
     enum operator op;
127
     struct expression *left;
128
     struct expression *right;
129
{
130
  struct expression *args[2];
131
 
132
  args[0] = left;
133
  args[1] = right;
134
  return new_exp (2, op, args);
135
}
136
 
137
static inline struct expression *
138
new_exp_3 (op, bexp, tbranch, fbranch)
139
     enum operator op;
140
     struct expression *bexp;
141
     struct expression *tbranch;
142
     struct expression *fbranch;
143
{
144
  struct expression *args[3];
145
 
146
  args[0] = bexp;
147
  args[1] = tbranch;
148
  args[2] = fbranch;
149
  return new_exp (3, op, args);
150
}
151
 
152
%}
153
 
154
/* This declares that all operators have the same associativity and the
155
   precedence order as in C.  See [Harbison, Steele: C, A Reference Manual].
156
   There is no unary minus and no bitwise operators.
157
   Operators with the same syntactic behaviour have been merged into a single
158
   token, to save space in the array generated by bison.  */
159
%right '?'              /*   ?          */
160
%left '|'               /*   ||         */
161
%left '&'               /*   &&         */
162
%left EQUOP2            /*   == !=      */
163
%left CMPOP2            /*   < > <= >= */
164
%left ADDOP2            /*   + -        */
165
%left MULOP2            /*   * / %      */
166
%right '!'              /*   !          */
167
 
168
%token  EQUOP2 CMPOP2 ADDOP2 MULOP2
169
%token  NUMBER
170
%type  exp
171
 
172
%%
173
 
174
start:    exp
175
          {
176
            if ($1 == NULL)
177
              YYABORT;
178
            ((struct parse_args *) arg)->res = $1;
179
          }
180
        ;
181
 
182
exp:      exp '?' exp ':' exp
183
          {
184
            $$ = new_exp_3 (qmop, $1, $3, $5);
185
          }
186
        | exp '|' exp
187
          {
188
            $$ = new_exp_2 (lor, $1, $3);
189
          }
190
        | exp '&' exp
191
          {
192
            $$ = new_exp_2 (land, $1, $3);
193
          }
194
        | exp EQUOP2 exp
195
          {
196
            $$ = new_exp_2 ($2, $1, $3);
197
          }
198
        | exp CMPOP2 exp
199
          {
200
            $$ = new_exp_2 ($2, $1, $3);
201
          }
202
        | exp ADDOP2 exp
203
          {
204
            $$ = new_exp_2 ($2, $1, $3);
205
          }
206
        | exp MULOP2 exp
207
          {
208
            $$ = new_exp_2 ($2, $1, $3);
209
          }
210
        | '!' exp
211
          {
212
            $$ = new_exp_1 (lnot, $2);
213
          }
214
        | 'n'
215
          {
216
            $$ = new_exp_0 (var);
217
          }
218
        | NUMBER
219
          {
220
            if (($$ = new_exp_0 (num)) != NULL)
221
              $$->val.num = $1;
222
          }
223
        | '(' exp ')'
224
          {
225
            $$ = $2;
226
          }
227
        ;
228
 
229
%%
230
 
231
void
232
internal_function
233
FREE_EXPRESSION (exp)
234
     struct expression *exp;
235
{
236
  if (exp == NULL)
237
    return;
238
 
239
  /* Handle the recursive case.  */
240
  switch (exp->nargs)
241
    {
242
    case 3:
243
      FREE_EXPRESSION (exp->val.args[2]);
244
      /* FALLTHROUGH */
245
    case 2:
246
      FREE_EXPRESSION (exp->val.args[1]);
247
      /* FALLTHROUGH */
248
    case 1:
249
      FREE_EXPRESSION (exp->val.args[0]);
250
      /* FALLTHROUGH */
251
    default:
252
      break;
253
    }
254
 
255
  free (exp);
256
}
257
 
258
 
259
static int
260
yylex (lval, pexp)
261
     YYSTYPE *lval;
262
     const char **pexp;
263
{
264
  const char *exp = *pexp;
265
  int result;
266
 
267
  while (1)
268
    {
269
      if (exp[0] == '\0')
270
        {
271
          *pexp = exp;
272
          return YYEOF;
273
        }
274
 
275
      if (exp[0] != ' ' && exp[0] != '\t')
276
        break;
277
 
278
      ++exp;
279
    }
280
 
281
  result = *exp++;
282
  switch (result)
283
    {
284
    case '0': case '1': case '2': case '3': case '4':
285
    case '5': case '6': case '7': case '8': case '9':
286
      {
287
        unsigned long int n = result - '0';
288
        while (exp[0] >= '0' && exp[0] <= '9')
289
          {
290
            n *= 10;
291
            n += exp[0] - '0';
292
            ++exp;
293
          }
294
        lval->num = n;
295
        result = NUMBER;
296
      }
297
      break;
298
 
299
    case '=':
300
      if (exp[0] == '=')
301
        {
302
          ++exp;
303
          lval->op = equal;
304
          result = EQUOP2;
305
        }
306
      else
307
        result = YYERRCODE;
308
      break;
309
 
310
    case '!':
311
      if (exp[0] == '=')
312
        {
313
          ++exp;
314
          lval->op = not_equal;
315
          result = EQUOP2;
316
        }
317
      break;
318
 
319
    case '&':
320
    case '|':
321
      if (exp[0] == result)
322
        ++exp;
323
      else
324
        result = YYERRCODE;
325
      break;
326
 
327
    case '<':
328
      if (exp[0] == '=')
329
        {
330
          ++exp;
331
          lval->op = less_or_equal;
332
        }
333
      else
334
        lval->op = less_than;
335
      result = CMPOP2;
336
      break;
337
 
338
    case '>':
339
      if (exp[0] == '=')
340
        {
341
          ++exp;
342
          lval->op = greater_or_equal;
343
        }
344
      else
345
        lval->op = greater_than;
346
      result = CMPOP2;
347
      break;
348
 
349
    case '*':
350
      lval->op = mult;
351
      result = MULOP2;
352
      break;
353
 
354
    case '/':
355
      lval->op = divide;
356
      result = MULOP2;
357
      break;
358
 
359
    case '%':
360
      lval->op = module;
361
      result = MULOP2;
362
      break;
363
 
364
    case '+':
365
      lval->op = plus;
366
      result = ADDOP2;
367
      break;
368
 
369
    case '-':
370
      lval->op = minus;
371
      result = ADDOP2;
372
      break;
373
 
374
    case 'n':
375
    case '?':
376
    case ':':
377
    case '(':
378
    case ')':
379
      /* Nothing, just return the character.  */
380
      break;
381
 
382
    case ';':
383
    case '\n':
384
    case '\0':
385
      /* Be safe and let the user call this function again.  */
386
      --exp;
387
      result = YYEOF;
388
      break;
389
 
390
    default:
391
      result = YYERRCODE;
392
#if YYDEBUG != 0
393
      --exp;
394
#endif
395
      break;
396
    }
397
 
398
  *pexp = exp;
399
 
400
  return result;
401
}
402
 
403
 
404
static void
405
yyerror (str)
406
     const char *str;
407
{
408
  /* Do nothing.  We don't print error messages here.  */
409
}

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