Subversion Repositories openrisc_2011-10-31

! { dg-do run }

! This checks the patch for PR25395, in which equivalences within one

! segment were broken by indirect equivalences, depending on the

! offset of the variable that bridges the indirect equivalence.

!

! This is a fortran95 version of the original testcase, which was

! contributed by Harald Vogt  

program check_6

  common /abc/ mwkx(80)

  common /cde/ lischk(20)

  dimension    listpr(20),lisbit(10),lispat(8)

! This was badly compiled in the PR:

  equivalence (listpr(10),lisbit(1),mwkx(10)), &

              (lispat(1),listpr(10))

  lischk = (/0, 0, 0, 0, 0, 0, 0, 0, 0, 1, &

             2, 0, 0, 5, 6, 7, 8, 9,10, 0/)

  call set_arrays (listpr, lisbit)

  if (any (listpr.ne.lischk)) call abort ()

  call sub1

  call sub2

  call sub3

end

subroutine sub1

  common /abc/ mwkx(80)

  common /cde/ lischk(20)

  dimension    listpr(20),lisbit(10),lispat(8)

!     This workaround was OK

  equivalence (listpr(10),lisbit(1)), &

              (listpr(10),mwkx(10)),  &

              (listpr(10),lispat(1))

  call set_arrays (listpr, lisbit)

  if (any (listpr .ne. lischk)) call abort ()

end

!

! Equivalences not in COMMON

!___________________________

! This gave incorrect results for the same reason as in MAIN.

subroutine sub2

  dimension   mwkx(80)

  common /cde/ lischk(20)

  dimension    listpr(20),lisbit(10),lispat(8)

  equivalence (lispat(1),listpr(10)), &

              (mwkx(10),lisbit(1),listpr(10))

  call set_arrays (listpr, lisbit)

  if (any (listpr .ne. lischk)) call abort ()

end

! This gave correct results because the order in which the

! equivalences are taken is different and was given in the PR.

subroutine sub3

  dimension   mwkx(80)

  common /cde/ lischk(20)

  dimension    listpr(20),lisbit(10),lispat(8)

  equivalence (listpr(10),lisbit(1),mwkx(10)), &

              (lispat(1),listpr(10))

  call set_arrays (listpr, lisbit)

  if (any (listpr .ne. lischk)) call abort ()

end

subroutine set_arrays (listpr, lisbit)

  dimension listpr(20),lisbit(10)

  listpr = 0

  lisbit = (/(i, i = 1, 10)/)

  lisbit((/3,4/)) = 0

end