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! { dg-do compile }

! PR fortran/20858

! If we have "x = null(i)", then "null()" acquires the type, kind type,

! and rank of i and these need to match those of x.

program null_1

   integer, parameter :: sp = kind(1.e0), dp = kind(1.d0)

   integer,  pointer :: i => null()

   real(sp), pointer :: x => null()

   real(dp), pointer :: y => null()

   real(sp), pointer :: z(:) => null()

   x => null(i)     ! { dg-error "types in pointer assignment" }

   x => null(y)     ! { dg-error "types in pointer assignment" }

   z => null(i)     ! { dg-error "types in pointer assignment" }

   z => null(y)     ! { dg-error "types in pointer assignment" }

   x => null(z)     ! { dg-error "ranks in pointer assignment" }

   z => null(x)     ! { dg-error "ranks in pointer assignment" }

   z => null(z)

   nullify(i, x, y, z)

end program null_1