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// PR c++/16405

// { dg-options "-O2" }

// { dg-do run }

// There should be exactly one temporary generated for the code in "f"

// below when optimizing -- for the result of "b + c".  We have no

// easy way of checking that directly, so we count the number of calls

// to "memcpy", which is used on (some?) targets to copy temporaries.

// If there is more than two calls (one for coping "*this" to "t", and

// one for copying the temporary to "a"), then there are too many

// temporaries.

int i;

extern "C"

void *memcpy (void *dest, const void *src, __SIZE_TYPE__ n)

{

  char *d = (char *) dest;

  const char *s = (const char *) src;

  while (n--)

    d[n] = s[n];

  ++i;

  return dest;

}

struct T {

#ifdef __SPU__

  /* SPU returns aggregates up to 1172 bytes in registers.  */

  int a[300];

#else

  int a[128];

#endif

  T &operator+=(T const &v) __attribute__((noinline));

  T operator+(T const &v) const { T t = *this; t += v; return t; }

};

T &T::operator+=(T const &v) {

  return *this;

}

T a, b, c;

void f() { a = b + c; }

int main () {

  i = 0;

  f();

  if (i > 2)

    return 1;

}