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[/] [openrisc/] [trunk/] [gnu-src/] [gcc-4.5.1/] [gcc/] [testsuite/] [gcc.dg/] [tree-ssa/] [prefetch-6.c] - Blame information for rev 298

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1 298 jeremybenn
/* { dg-do compile { target i?86-*-* x86_64-*-* } } */
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/* { dg-require-effective-target ilp32 } */
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/* { dg-require-effective-target sse2 } */
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/* { dg-options "-O2 -fprefetch-loop-arrays -march=athlon -msse2 -mfpmath=sse --param simultaneous-prefetches=100 -fdump-tree-aprefetch-details" } */
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#define N 1000
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#define K 900
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double a[N][N];
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double test(void)
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{
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  unsigned i, j;
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  double sum = 0;
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  /* Here, we should use non-temporal prefetch instruction.  */
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  for (i = 0; i < K; i++)
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    for (j = 0; j < K; j++)
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      sum += a[i][j];
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  /* Here, we should not use non-temporal prefetch instruction, since the
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     value of a[i+10][j] is reused in L2 cache.  */
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  for (i = 0; i < K; i++)
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    for (j = 0; j < K; j++)
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      sum += a[i][j] * a[i + 10][j];
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  /* Here, we should use non-temporal prefetch instruction, since the
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     value of a[i+100][j] is too far to be reused in L2 cache.  */
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  for (i = 0; i < K; i++)
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    for (j = 0; j < K; j++)
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      sum += a[i][j] * a[i + 100][j];
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  /* Here, temporal prefetches should be used, since the volume of the
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     memory accesses is smaller than L2 cache.  */
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  for (i = 0; i < 100; i++)
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    for (j = 0; j < 100; j++)
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      sum += a[i][j] * a[i + 100][j];
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  /* Temporal prefetches should be used here (even though the accesses to
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     a[j][i] are independent, the same cache line is almost always hit
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     every N iterations).  */
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  for (i = 0; i < N; i++)
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    for (j = 0; j < N; j++)
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      sum += a[j][i];
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  return sum;
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}
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/* { dg-final { scan-tree-dump-times "Issued prefetch" 5 "aprefetch" } } */
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/* { dg-final { scan-tree-dump-times "Issued nontemporal prefetch" 3 "aprefetch" } } */
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/* { dg-final { scan-assembler-times "prefetcht" 5 } } */
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/* { dg-final { scan-assembler-times "prefetchnta" 3 } } */
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/* { dg-final { cleanup-tree-dump "aprefetch" } } */

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