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/* { dg-require-effective-target vect_int } */

/* { dg-require-effective-target vect_float } */

#include <stdarg.h>

#include <string.h>

#include "tree-vect.h"

#define N 256

__attribute__ ((noinline))

void bar (float *pa, float *pb, float *pc)

{

  int i;

  /* check results:  */

  for (i = 0; i < N/2; i++)

    {

      if (pa[i] != (pb[i+1] * pc[i+1]))

        abort ();

    }

  return;

}

__attribute__ ((noinline))

void foo (float *pb, float *pc)

{

  float b[N] = {0,3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54,57};

  float c[N] = {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19};

  memcpy (pb, b, sizeof (b));

  memcpy (pc, c, sizeof (c));

}

/* Unaligned pointer read accesses with known alignment,

   and an unaligned write access with unknown alignment.

   The loop bound is iunknown.

   Can't prove that the pointers don't alias.

   vect-57.c is similar to this one with one difference:

        the loop bound is known.

   vect-60.c is similar to this one with two differences:

        aliasing is not a problem, and the write access is unaligned.  */

__attribute__ ((noinline)) int

main1 (int n , float *pa)

{

  int i;

  float b[N] __attribute__ ((__aligned__(__BIGGEST_ALIGNMENT__)));

  float c[N] __attribute__ ((__aligned__(__BIGGEST_ALIGNMENT__)));

  float *pb = b;

  float *pc = c;

  foo (pb, pc);

  for (i = 0; i < n/2; i++)

    {

      pa[i] = pb[i+1] * pc[i+1];

    }

  bar (pa,pb,pc);

  return 0;

}

int main (void)

{

  int i;

  int n=N;

  float a[N] __attribute__ ((__aligned__(__BIGGEST_ALIGNMENT__)));

  check_vect ();

  main1 (n,a);

  return 0;

}

/* { dg-final { scan-tree-dump-times "vectorized 1 loops" 1 "vect" { xfail vect_no_align } } } */

/* { dg-final { cleanup-tree-dump "vect" } } */