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[/] [openrisc/] [trunk/] [gnu-src/] [gdb-6.8/] [intl/] [plural.y] - Blame information for rev 298

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1 24 jeremybenn
%{
2
/* Expression parsing for plural form selection.
3
   Copyright (C) 2000, 2001 Free Software Foundation, Inc.
4
   Written by Ulrich Drepper , 2000.
5
 
6
   This program is free software; you can redistribute it and/or modify it
7
   under the terms of the GNU Library General Public License as published
8
   by the Free Software Foundation; either version 2, or (at your option)
9
   any later version.
10
 
11
   This program is distributed in the hope that it will be useful,
12
   but WITHOUT ANY WARRANTY; without even the implied warranty of
13
   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
14
   Library General Public License for more details.
15
 
16
   You should have received a copy of the GNU Library General Public
17
   License along with this program; if not, write to the Free Software
18
   Foundation, Inc., 51 Franklin Street - Fifth Floor, Boston, MA 02110-1301,
19
   USA.  */
20
 
21
/* The bison generated parser uses alloca.  AIX 3 forces us to put this
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   declaration at the beginning of the file.  The declaration in bison's
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   skeleton file comes too late.  This must come before 
24
   because  may include arbitrary system headers.  */
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#if defined _AIX && !defined __GNUC__
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 #pragma alloca
27
#endif
28
 
29
#ifdef HAVE_CONFIG_H
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# include 
31
#endif
32
 
33
#include 
34
#include 
35
#include "plural-exp.h"
36
 
37
/* The main function generated by the parser is called __gettextparse,
38
   but we want it to be called PLURAL_PARSE.  */
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#ifndef _LIBC
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# define __gettextparse PLURAL_PARSE
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#endif
42
 
43
#define YYLEX_PARAM     &((struct parse_args *) arg)->cp
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#define YYPARSE_PARAM   arg
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%}
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%pure_parser
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%expect 7
48
 
49
%union {
50
  unsigned long int num;
51
  enum operator op;
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  struct expression *exp;
53
}
54
 
55
%{
56
/* Prototypes for local functions.  */
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static struct expression *new_exp PARAMS ((int nargs, enum operator op,
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                                           struct expression * const *args));
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static inline struct expression *new_exp_0 PARAMS ((enum operator op));
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static inline struct expression *new_exp_1 PARAMS ((enum operator op,
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                                                   struct expression *right));
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static struct expression *new_exp_2 PARAMS ((enum operator op,
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                                             struct expression *left,
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                                             struct expression *right));
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static inline struct expression *new_exp_3 PARAMS ((enum operator op,
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                                                   struct expression *bexp,
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                                                   struct expression *tbranch,
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                                                   struct expression *fbranch));
69
static int yylex PARAMS ((YYSTYPE *lval, const char **pexp));
70
static void yyerror PARAMS ((const char *str));
71
 
72
/* Allocation of expressions.  */
73
 
74
static struct expression *
75
new_exp (nargs, op, args)
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     int nargs;
77
     enum operator op;
78
     struct expression * const *args;
79
{
80
  int i;
81
  struct expression *newp;
82
 
83
  /* If any of the argument could not be malloc'ed, just return NULL.  */
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  for (i = nargs - 1; i >= 0; i--)
85
    if (args[i] == NULL)
86
      goto fail;
87
 
88
  /* Allocate a new expression.  */
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  newp = (struct expression *) malloc (sizeof (*newp));
90
  if (newp != NULL)
91
    {
92
      newp->nargs = nargs;
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      newp->operation = op;
94
      for (i = nargs - 1; i >= 0; i--)
95
        newp->val.args[i] = args[i];
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      return newp;
97
    }
98
 
99
 fail:
100
  for (i = nargs - 1; i >= 0; i--)
101
    FREE_EXPRESSION (args[i]);
102
 
103
  return NULL;
104
}
105
 
106
static inline struct expression *
107
new_exp_0 (op)
108
     enum operator op;
109
{
110
  return new_exp (0, op, NULL);
111
}
112
 
113
static inline struct expression *
114
new_exp_1 (op, right)
115
     enum operator op;
116
     struct expression *right;
117
{
118
  struct expression *args[1];
119
 
120
  args[0] = right;
121
  return new_exp (1, op, args);
122
}
123
 
124
static struct expression *
125
new_exp_2 (op, left, right)
126
     enum operator op;
127
     struct expression *left;
128
     struct expression *right;
129
{
130
  struct expression *args[2];
131
 
132
  args[0] = left;
133
  args[1] = right;
134
  return new_exp (2, op, args);
135
}
136
 
137
static inline struct expression *
138
new_exp_3 (op, bexp, tbranch, fbranch)
139
     enum operator op;
140
     struct expression *bexp;
141
     struct expression *tbranch;
142
     struct expression *fbranch;
143
{
144
  struct expression *args[3];
145
 
146
  args[0] = bexp;
147
  args[1] = tbranch;
148
  args[2] = fbranch;
149
  return new_exp (3, op, args);
150
}
151
 
152
%}
153
 
154
/* This declares that all operators have the same associativity and the
155
   precedence order as in C.  See [Harbison, Steele: C, A Reference Manual].
156
   There is no unary minus and no bitwise operators.
157
   Operators with the same syntactic behaviour have been merged into a single
158
   token, to save space in the array generated by bison.  */
159
%right '?'              /*   ?          */
160
%left '|'               /*   ||         */
161
%left '&'               /*   &&         */
162
%left EQUOP2            /*   == !=      */
163
%left CMPOP2            /*   < > <= >= */
164
%left ADDOP2            /*   + -        */
165
%left MULOP2            /*   * / %      */
166
%right '!'              /*   !          */
167
 
168
%token  EQUOP2 CMPOP2 ADDOP2 MULOP2
169
%token  NUMBER
170
%type  exp
171
 
172
%%
173
 
174
start:    exp
175
          {
176
            if ($1 == NULL)
177
              YYABORT;
178
            ((struct parse_args *) arg)->res = $1;
179
          }
180
        ;
181
 
182
exp:      exp '?' exp ':' exp
183
          {
184
            $$ = new_exp_3 (qmop, $1, $3, $5);
185
          }
186
        | exp '|' exp
187
          {
188
            $$ = new_exp_2 (lor, $1, $3);
189
          }
190
        | exp '&' exp
191
          {
192
            $$ = new_exp_2 (land, $1, $3);
193
          }
194
        | exp EQUOP2 exp
195
          {
196
            $$ = new_exp_2 ($2, $1, $3);
197
          }
198
        | exp CMPOP2 exp
199
          {
200
            $$ = new_exp_2 ($2, $1, $3);
201
          }
202
        | exp ADDOP2 exp
203
          {
204
            $$ = new_exp_2 ($2, $1, $3);
205
          }
206
        | exp MULOP2 exp
207
          {
208
            $$ = new_exp_2 ($2, $1, $3);
209
          }
210
        | '!' exp
211
          {
212
            $$ = new_exp_1 (lnot, $2);
213
          }
214
        | 'n'
215
          {
216
            $$ = new_exp_0 (var);
217
          }
218
        | NUMBER
219
          {
220
            if (($$ = new_exp_0 (num)) != NULL)
221
              $$->val.num = $1;
222
          }
223
        | '(' exp ')'
224
          {
225
            $$ = $2;
226
          }
227
        ;
228
 
229
%%
230
 
231
void
232
internal_function
233
FREE_EXPRESSION (exp)
234
     struct expression *exp;
235
{
236
  if (exp == NULL)
237
    return;
238
 
239
  /* Handle the recursive case.  */
240
  switch (exp->nargs)
241
    {
242
    case 3:
243
      FREE_EXPRESSION (exp->val.args[2]);
244
      /* FALLTHROUGH */
245
    case 2:
246
      FREE_EXPRESSION (exp->val.args[1]);
247
      /* FALLTHROUGH */
248
    case 1:
249
      FREE_EXPRESSION (exp->val.args[0]);
250
      /* FALLTHROUGH */
251
    default:
252
      break;
253
    }
254
 
255
  free (exp);
256
}
257
 
258
 
259
static int
260
yylex (lval, pexp)
261
     YYSTYPE *lval;
262
     const char **pexp;
263
{
264
  const char *exp = *pexp;
265
  int result;
266
 
267
  while (1)
268
    {
269
      if (exp[0] == '\0')
270
        {
271
          *pexp = exp;
272
          return YYEOF;
273
        }
274
 
275
      if (exp[0] != ' ' && exp[0] != '\t')
276
        break;
277
 
278
      ++exp;
279
    }
280
 
281
  result = *exp++;
282
  switch (result)
283
    {
284
    case '0': case '1': case '2': case '3': case '4':
285
    case '5': case '6': case '7': case '8': case '9':
286
      {
287
        unsigned long int n = result - '0';
288
        while (exp[0] >= '0' && exp[0] <= '9')
289
          {
290
            n *= 10;
291
            n += exp[0] - '0';
292
            ++exp;
293
          }
294
        lval->num = n;
295
        result = NUMBER;
296
      }
297
      break;
298
 
299
    case '=':
300
      if (exp[0] == '=')
301
        {
302
          ++exp;
303
          lval->op = equal;
304
          result = EQUOP2;
305
        }
306
      else
307
        result = YYERRCODE;
308
      break;
309
 
310
    case '!':
311
      if (exp[0] == '=')
312
        {
313
          ++exp;
314
          lval->op = not_equal;
315
          result = EQUOP2;
316
        }
317
      break;
318
 
319
    case '&':
320
    case '|':
321
      if (exp[0] == result)
322
        ++exp;
323
      else
324
        result = YYERRCODE;
325
      break;
326
 
327
    case '<':
328
      if (exp[0] == '=')
329
        {
330
          ++exp;
331
          lval->op = less_or_equal;
332
        }
333
      else
334
        lval->op = less_than;
335
      result = CMPOP2;
336
      break;
337
 
338
    case '>':
339
      if (exp[0] == '=')
340
        {
341
          ++exp;
342
          lval->op = greater_or_equal;
343
        }
344
      else
345
        lval->op = greater_than;
346
      result = CMPOP2;
347
      break;
348
 
349
    case '*':
350
      lval->op = mult;
351
      result = MULOP2;
352
      break;
353
 
354
    case '/':
355
      lval->op = divide;
356
      result = MULOP2;
357
      break;
358
 
359
    case '%':
360
      lval->op = module;
361
      result = MULOP2;
362
      break;
363
 
364
    case '+':
365
      lval->op = plus;
366
      result = ADDOP2;
367
      break;
368
 
369
    case '-':
370
      lval->op = minus;
371
      result = ADDOP2;
372
      break;
373
 
374
    case 'n':
375
    case '?':
376
    case ':':
377
    case '(':
378
    case ')':
379
      /* Nothing, just return the character.  */
380
      break;
381
 
382
    case ';':
383
    case '\n':
384
    case '\0':
385
      /* Be safe and let the user call this function again.  */
386
      --exp;
387
      result = YYEOF;
388
      break;
389
 
390
    default:
391
      result = YYERRCODE;
392
#if YYDEBUG != 0
393
      --exp;
394
#endif
395
      break;
396
    }
397
 
398
  *pexp = exp;
399
 
400
  return result;
401
}
402
 
403
 
404
static void
405
yyerror (str)
406
     const char *str;
407
{
408
  /* Do nothing.  We don't print error messages here.  */
409
}

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