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[/] [openrisc/] [trunk/] [gnu-stable/] [newlib-1.18.0/] [newlib/] [libc/] [stdlib/] [lldiv.c] - Blame information for rev 829

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1 207 jeremybenn
/*
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FUNCTION
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<<lldiv>>---divide two long long integers
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INDEX
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        lldiv
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ANSI_SYNOPSIS
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        #include <stdlib.h>
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        lldiv_t lldiv(long long <[n]>, long long <[d]>);
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TRAD_SYNOPSIS
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        #include <stdlib.h>
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        lldiv_t lldiv(<[n]>, <[d]>)
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        long long <[n]>, <[d]>;
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DESCRIPTION
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Divide
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@tex
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$n/d$,
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@end tex
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@ifnottex
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<[n]>/<[d]>,
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@end ifnottex
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returning quotient and remainder as two long long integers in a structure
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<<lldiv_t>>.
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RETURNS
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The result is represented with the structure
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. typedef struct
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. {
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.  long long quot;
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.  long long rem;
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. } lldiv_t;
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where the <<quot>> field represents the quotient, and <<rem>> the
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remainder.  For nonzero <[d]>, if `<<<[r]> = ldiv(<[n]>,<[d]>);>>' then
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<[n]> equals `<<<[r]>.rem + <[d]>*<[r]>.quot>>'.
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To divide <<long>> rather than <<long long>> values, use the similar
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function <<ldiv>>.
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PORTABILITY
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<<lldiv>> is ISO 9899 (C99) compatable.
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No supporting OS subroutines are required.
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*/
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/*-
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 * Copyright (c) 2001 Mike Barcroft <mike@FreeBSD.org>
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 * All rights reserved.
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 *
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 * Redistribution and use in source and binary forms, with or without
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 * modification, are permitted provided that the following conditions
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 * are met:
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 * 1. Redistributions of source code must retain the above copyright
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 *    notice, this list of conditions and the following disclaimer.
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 * 2. Redistributions in binary form must reproduce the above copyright
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 *    notice, this list of conditions and the following disclaimer in the
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 *    documentation and/or other materials provided with the distribution.
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 *
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 * THIS SOFTWARE IS PROVIDED BY THE AUTHOR AND CONTRIBUTORS ``AS IS'' AND
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 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
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 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
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 * ARE DISCLAIMED.  IN NO EVENT SHALL THE AUTHOR OR CONTRIBUTORS BE LIABLE
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 * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
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 * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
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 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
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 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
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 * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
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 * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
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 * SUCH DAMAGE.
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 */
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#include <stdlib.h>
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/*
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 * The ANSI standard says that |r.quot| <= |n/d|, where
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 * n/d is to be computed in infinite precision.  In other
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 * words, we should always truncate the quotient towards
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 * 0, never -infinity.
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 *
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 * Machine division and remainer may work either way when
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 * one or both of n or d is negative.  If only one is
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 * negative and r.quot has been truncated towards -inf,
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 * r.rem will have the same sign as denom and the opposite
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 * sign of num; if both are negative and r.quot has been
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 * truncated towards -inf, r.rem will be positive (will
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 * have the opposite sign of num).  These are considered
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 * `wrong'.
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 *
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 * If both are num and denom are positive, r will always
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 * be positive.
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 *
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 * This all boils down to:
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 *      if num >= 0, but r.rem < 0, we got the wrong answer.
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 * In that case, to get the right answer, add 1 to r.quot and
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 * subtract denom from r.rem.
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 */
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lldiv_t
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_DEFUN (lldiv, (number, denom),
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       long long numer _AND long long denom)
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{
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        lldiv_t retval;
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        retval.quot = numer / denom;
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        retval.rem = numer % denom;
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        if (numer >= 0 && retval.rem < 0) {
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                retval.quot++;
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                retval.rem -= denom;
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        }
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        return (retval);
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}
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