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/* Allocate memory region filled with spaces.

   Copyright (C) 1991 Free Software Foundation, Inc.

This file is part of the libiberty library.

Libiberty is free software; you can redistribute it and/or

modify it under the terms of the GNU Library General Public

License as published by the Free Software Foundation; either

version 2 of the License, or (at your option) any later version.

Libiberty is distributed in the hope that it will be useful,

but WITHOUT ANY WARRANTY; without even the implied warranty of

MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU

Library General Public License for more details.

You should have received a copy of the GNU Library General Public

License along with libiberty; see the file COPYING.LIB.  If

not, write to the Free Software Foundation, Inc., 59 Temple Place - Suite 330,

Boston, MA 02111-1307, USA.  */

/*

NAME

        spaces -- return a pointer to a buffer full of spaces

SYNOPSIS

        char *spaces (int count)

DESCRIPTION

        Returns a pointer to a memory region filled with the specified

        number of spaces and null terminated.  The returned pointer is

        valid until at least the next call.

BUGS

*/

#include "ansidecl.h"

#include "libiberty.h"

#if VMS

#include <stdlib.h>

#include <unixlib.h>

#else

/* For systems with larger pointers than ints, these must be declared.  */

extern PTR malloc PARAMS ((size_t));

extern void free PARAMS ((PTR));

#endif

const char *

spaces (count)

  int count;

{

  register char *t;

  static char *buf;

  static int maxsize;

  if (count > maxsize)

    {

      if (buf)

        {

          free (buf);

        }

      buf = malloc (count + 1);

      if (buf == (char *) 0)

        return 0;

      for (t = buf + count ; t != buf ; )

        {

          *--t = ' ';

        }

      maxsize = count;

      buf[count] = '\0';

    }

  return (const char *) (buf + maxsize - count);

}