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[/] [or1k/] [trunk/] [rc203soc/] [sw/] [uClinux/] [arch/] [m68k/] [fpsp040/] [binstr.S] - Blame information for rev 1765

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Line No. Rev Author Line
1 1623 jcastillo
|
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|       binstr.sa 3.3 12/19/90
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|
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|       Description: Converts a 64-bit binary integer to bcd.
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|
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|       Input: 64-bit binary integer in d2:d3, desired length (LEN) in
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|          d0, and a  pointer to start in memory for bcd characters
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|          in d0. (This pointer must point to byte 4 of the first
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|          lword of the packed decimal memory string.)
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|
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|       Output: LEN bcd digits representing the 64-bit integer.
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|
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|       Algorithm:
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|               The 64-bit binary is assumed to have a decimal point before
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|               bit 63.  The fraction is multiplied by 10 using a mul by 2
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|               shift and a mul by 8 shift.  The bits shifted out of the
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|               msb form a decimal digit.  This process is iterated until
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|               LEN digits are formed.
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|
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|       A1. Init d7 to 1.  D7 is the byte digit counter, and if 1, the
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|               digit formed will be assumed the least significant.  This is
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|               to force the first byte formed to have a 0 in the upper 4 bits.
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|
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|       A2. Beginning of the loop:
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|               Copy the fraction in d2:d3 to d4:d5.
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|
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|       A3. Multiply the fraction in d2:d3 by 8 using bit-field
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|               extracts and shifts.  The three msbs from d2 will go into
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|               d1.
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|
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|       A4. Multiply the fraction in d4:d5 by 2 using shifts.  The msb
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|               will be collected by the carry.
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|
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|       A5. Add using the carry the 64-bit quantities in d2:d3 and d4:d5
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|               into d2:d3.  D1 will contain the bcd digit formed.
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|
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|       A6. Test d7.  If zero, the digit formed is the ms digit.  If non-
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|               zero, it is the ls digit.  Put the digit in its place in the
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|               upper word of d0.  If it is the ls digit, write the word
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|               from d0 to memory.
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|
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|       A7. Decrement d6 (LEN counter) and repeat the loop until zero.
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|
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|       Implementation Notes:
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|
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|       The registers are used as follows:
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|
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|               d0: LEN counter
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|               d1: temp used to form the digit
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|               d2: upper 32-bits of fraction for mul by 8
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|               d3: lower 32-bits of fraction for mul by 8
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|               d4: upper 32-bits of fraction for mul by 2
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|               d5: lower 32-bits of fraction for mul by 2
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|               d6: temp for bit-field extracts
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|               d7: byte digit formation word;digit count {0,1}
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|               a0: pointer into memory for packed bcd string formation
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|
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|               Copyright (C) Motorola, Inc. 1990
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|                       All Rights Reserved
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|
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|       THIS IS UNPUBLISHED PROPRIETARY SOURCE CODE OF MOTOROLA
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|       The copyright notice above does not evidence any
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|       actual or intended publication of such source code.
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|BINSTR    idnt    2,1 | Motorola 040 Floating Point Software Package
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        |section        8
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        .include "fpsp.h"
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        .global binstr
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binstr:
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        moveml  %d0-%d7,-(%a7)
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|
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| A1: Init d7
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        moveql  #1,%d7                  |init d7 for second digit
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        subql   #1,%d0                  |for dbf d0 would have LEN+1 passes
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|
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| A2. Copy d2:d3 to d4:d5.  Start loop.
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|
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loop:
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        movel   %d2,%d4                 |copy the fraction before muls
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        movel   %d3,%d5                 |to d4:d5
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| A3. Multiply d2:d3 by 8; extract msbs into d1.
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        bfextu  %d2{#0:#3},%d1          |copy 3 msbs of d2 into d1
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        asll    #3,%d2                  |shift d2 left by 3 places
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        bfextu  %d3{#0:#3},%d6          |copy 3 msbs of d3 into d6
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        asll    #3,%d3                  |shift d3 left by 3 places
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        orl     %d6,%d2                 |or in msbs from d3 into d2
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| A4. Multiply d4:d5 by 2; add carry out to d1.
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        asll    #1,%d5                  |mul d5 by 2
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        roxll   #1,%d4                  |mul d4 by 2
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        swap    %d6                     |put 0 in d6 lower word
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        addxw   %d6,%d1                 |add in extend from mul by 2
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| A5. Add mul by 8 to mul by 2.  D1 contains the digit formed.
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        addl    %d5,%d3                 |add lower 32 bits
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        nop                             |ERRATA ; FIX #13 (Rev. 1.2 6/6/90)
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        addxl   %d4,%d2                 |add with extend upper 32 bits
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        nop                             |ERRATA ; FIX #13 (Rev. 1.2 6/6/90)
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        addxw   %d6,%d1                 |add in extend from add to d1
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        swap    %d6                     |with d6 = 0; put 0 in upper word
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| A6. Test d7 and branch.
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        tstw    %d7                     |if zero, store digit & to loop
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        beqs    first_d                 |if non-zero, form byte & write
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sec_d:
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        swap    %d7                     |bring first digit to word d7b
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        aslw    #4,%d7                  |first digit in upper 4 bits d7b
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        addw    %d1,%d7                 |add in ls digit to d7b
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        moveb   %d7,(%a0)+              |store d7b byte in memory
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        swap    %d7                     |put LEN counter in word d7a
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        clrw    %d7                     |set d7a to signal no digits done
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        dbf     %d0,loop                |do loop some more!
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        bras    end_bstr                |finished, so exit
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first_d:
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        swap    %d7                     |put digit word in d7b
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        movew   %d1,%d7                 |put new digit in d7b
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        swap    %d7                     |put LEN counter in word d7a
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        addqw   #1,%d7                  |set d7a to signal first digit done
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        dbf     %d0,loop                |do loop some more!
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        swap    %d7                     |put last digit in string
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        lslw    #4,%d7                  |move it to upper 4 bits
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        moveb   %d7,(%a0)+              |store it in memory string
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| Clean up and return with result in fp0.
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end_bstr:
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        moveml  (%a7)+,%d0-%d7
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        rts
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        |end

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