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[/] [or1k/] [trunk/] [uclinux/] [uC-libc/] [misc/] [strtol.c] - Blame information for rev 1765

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1 199 simons
/*
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 * strtol.c - This file is part of the libc-8086 package for ELKS,
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 * Copyright (C) 1995, 1996 Nat Friedman <ndf@linux.mit.edu>.
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 *
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 *  This library is free software; you can redistribute it and/or
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 *  modify it under the terms of the GNU Library General Public
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 *  License as published by the Free Software Foundation; either
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 *  version 2 of the License, or (at your option) any later version.
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 *
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 *  This library is distributed in the hope that it will be useful,
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 *  but WITHOUT ANY WARRANTY; without even the implied warranty of
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 *  MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
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 *  Library General Public License for more details.
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 *
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 *  You should have received a copy of the GNU Library General Public
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 *  License along with this library; if not, write to the Free
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 *  Software Foundation, Inc., 675 Mass Ave, Cambridge, MA 02139, USA.
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 *
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 */
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#include <ctype.h>
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#include <stdlib.h>
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long int
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strtol(const char *nptr, char **endptr, int base)
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{
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  const char * ptr;
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  unsigned short negative;
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  long int number;
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  ptr=nptr;
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  while (isspace(*ptr))
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    ptr++;
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  negative=0;
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  if (*ptr=='-')
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    negative=1;
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  number=(long int)strtoul(nptr, endptr, base);
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  return (negative ? -number:number);
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}
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unsigned long int
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strtoul(const char *nptr, char **endptr, int base)
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{
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  unsigned long int number;
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  /* Sanity check the arguments */
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  if (base==1 || base>36 || base<0)
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    base=0;
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  /* advance beyond any leading whitespace */
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  while (isspace(*nptr))
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    nptr++;
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  /* check for optional '+' or '-' */
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  if (*nptr=='-')
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      nptr++;
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  else
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    if (*nptr=='+')
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      nptr++;
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  /* If base==0 and the string begins with "0x" then we're supposed
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     to assume that it's hexadecimal (base 16). */
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  else
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    if (base==0 && *nptr=='0')
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      if (toupper(*(nptr+1))=='X')
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        {
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          base=16;
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          nptr+=2;
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        }
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  /* If base==0 and the string begins with "0" but not "0x",
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     then we're supposed to assume that it's octal (base 8). */
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      else
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        {
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          base=8;
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          nptr++;
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        }
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  /* If base is still 0 (it was 0 to begin with and the string didn't begin
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     with "0"), then we are supposed to assume that it's base 10 */
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  if (base==0)
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    base=10;
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  number=0;
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  while (isalnum(*nptr))
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    {
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      number= (number*base)+((isalpha(*nptr) ? toupper(*nptr) : *nptr)
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                             - (isdigit(*nptr) ? '0' : 'A' - 10));
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      nptr++;
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      /*if (*nptr>'0'+base)
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        break;*/
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    }
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  /* Some code is simply _impossible_ to write with -Wcast-qual .. :-\ */
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  if (endptr!=NULL)
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    *endptr=(char *)nptr;
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  /* All done */
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  return number;
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}

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