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| stan.sa 3.3 7/29/91
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| The entry point stan computes the tangent of
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| an input argument;
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| stand does the same except for denormalized input.
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| Input: Double-extended number X in location pointed to
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| by address register a0.
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| Output: The value tan(X) returned in floating-point register Fp0.
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| Accuracy and Monotonicity: The returned result is within 3 ulp in
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| 64 significant bit, i.e. within 0.5001 ulp to 53 bits if the
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| result is subsequently rounded to double precision. The
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| result is provably monotonic in double precision.
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| Speed: The program sTAN takes approximately 170 cycles for
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| input argument X such that |X| < 15Pi, which is the usual
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| situation.
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| Algorithm:
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| 1. If |X| >= 15Pi or |X| < 2**(-40), go to 6.
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| 2. Decompose X as X = N(Pi/2) + r where |r| <= Pi/4. Let
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| k = N mod 2, so in particular, k = 0 or 1.
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| 3. If k is odd, go to 5.
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| 4. (k is even) Tan(X) = tan(r) and tan(r) is approximated by a
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| rational function U/V where
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| U = r + r*s*(P1 + s*(P2 + s*P3)), and
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| V = 1 + s*(Q1 + s*(Q2 + s*(Q3 + s*Q4))), s = r*r.
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| Exit.
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| 4. (k is odd) Tan(X) = -cot(r). Since tan(r) is approximated by a
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| rational function U/V where
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| U = r + r*s*(P1 + s*(P2 + s*P3)), and
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| V = 1 + s*(Q1 + s*(Q2 + s*(Q3 + s*Q4))), s = r*r,
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| -Cot(r) = -V/U. Exit.
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| 6. If |X| > 1, go to 8.
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| 7. (|X|<2**(-40)) Tan(X) = X. Exit.
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| 8. Overwrite X by X := X rem 2Pi. Now that |X| <= Pi, go back to 2.
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| Copyright (C) Motorola, Inc. 1990
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| All Rights Reserved
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| THIS IS UNPUBLISHED PROPRIETARY SOURCE CODE OF MOTOROLA
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| The copyright notice above does not evidence any
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| actual or intended publication of such source code.
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|STAN idnt 2,1 | Motorola 040 Floating Point Software Package
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|section 8
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.include "fpsp.h"
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BOUNDS1: .long 0x3FD78000,0x4004BC7E
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TWOBYPI: .long 0x3FE45F30,0x6DC9C883
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TANQ4: .long 0x3EA0B759,0xF50F8688
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TANP3: .long 0xBEF2BAA5,0xA8924F04
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TANQ3: .long 0xBF346F59,0xB39BA65F,0x00000000,0x00000000
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TANP2: .long 0x3FF60000,0xE073D3FC,0x199C4A00,0x00000000
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TANQ2: .long 0x3FF90000,0xD23CD684,0x15D95FA1,0x00000000
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TANP1: .long 0xBFFC0000,0x8895A6C5,0xFB423BCA,0x00000000
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TANQ1: .long 0xBFFD0000,0xEEF57E0D,0xA84BC8CE,0x00000000
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INVTWOPI: .long 0x3FFC0000,0xA2F9836E,0x4E44152A,0x00000000
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TWOPI1: .long 0x40010000,0xC90FDAA2,0x00000000,0x00000000
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TWOPI2: .long 0x3FDF0000,0x85A308D4,0x00000000,0x00000000
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|--N*PI/2, -32 <= N <= 32, IN A LEADING TERM IN EXT. AND TRAILING
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|--TERM IN SGL. NOTE THAT PI IS 64-BIT LONG, THUS N*PI/2 IS AT
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|--MOST 69 BITS LONG.
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.global PITBL
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PITBL:
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.long 0xC0040000,0xC90FDAA2,0x2168C235,0x21800000
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.long 0xC0040000,0xC2C75BCD,0x105D7C23,0xA0D00000
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.long 0xC0040000,0xBC7EDCF7,0xFF523611,0xA1E80000
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.long 0xC0040000,0xB6365E22,0xEE46F000,0x21480000
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.long 0xC0040000,0xAFEDDF4D,0xDD3BA9EE,0xA1200000
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.long 0xC0040000,0xA9A56078,0xCC3063DD,0x21FC0000
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.long 0xC0040000,0xA35CE1A3,0xBB251DCB,0x21100000
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.long 0xC0040000,0x9D1462CE,0xAA19D7B9,0xA1580000
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.long 0xC0040000,0x96CBE3F9,0x990E91A8,0x21E00000
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.long 0xC0040000,0x90836524,0x88034B96,0x20B00000
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.long 0xC0040000,0x8A3AE64F,0x76F80584,0xA1880000
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.long 0xC0040000,0x83F2677A,0x65ECBF73,0x21C40000
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.long 0xC0030000,0xFB53D14A,0xA9C2F2C2,0x20000000
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.long 0xC0030000,0xEEC2D3A0,0x87AC669F,0x21380000
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.long 0xC0030000,0xE231D5F6,0x6595DA7B,0xA1300000
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.long 0xC0030000,0xD5A0D84C,0x437F4E58,0x9FC00000
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.long 0xC0030000,0xC90FDAA2,0x2168C235,0x21000000
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.long 0xC0030000,0xBC7EDCF7,0xFF523611,0xA1680000
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.long 0xC0030000,0xAFEDDF4D,0xDD3BA9EE,0xA0A00000
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.long 0xC0030000,0xA35CE1A3,0xBB251DCB,0x20900000
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.long 0xC0030000,0x96CBE3F9,0x990E91A8,0x21600000
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.long 0xC0030000,0x8A3AE64F,0x76F80584,0xA1080000
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.long 0xC0020000,0xFB53D14A,0xA9C2F2C2,0x1F800000
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.long 0xC0020000,0xE231D5F6,0x6595DA7B,0xA0B00000
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.long 0xC0020000,0xC90FDAA2,0x2168C235,0x20800000
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.long 0xC0020000,0xAFEDDF4D,0xDD3BA9EE,0xA0200000
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.long 0xC0020000,0x96CBE3F9,0x990E91A8,0x20E00000
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.long 0xC0010000,0xFB53D14A,0xA9C2F2C2,0x1F000000
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.long 0xC0010000,0xC90FDAA2,0x2168C235,0x20000000
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.long 0xC0010000,0x96CBE3F9,0x990E91A8,0x20600000
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.long 0xC0000000,0xC90FDAA2,0x2168C235,0x1F800000
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.long 0xBFFF0000,0xC90FDAA2,0x2168C235,0x1F000000
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.long 0x00000000,0x00000000,0x00000000,0x00000000
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.long 0x3FFF0000,0xC90FDAA2,0x2168C235,0x9F000000
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.long 0x40000000,0xC90FDAA2,0x2168C235,0x9F800000
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.long 0x40010000,0x96CBE3F9,0x990E91A8,0xA0600000
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.long 0x40010000,0xC90FDAA2,0x2168C235,0xA0000000
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.long 0x40010000,0xFB53D14A,0xA9C2F2C2,0x9F000000
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.long 0x40020000,0x96CBE3F9,0x990E91A8,0xA0E00000
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.long 0x40020000,0xAFEDDF4D,0xDD3BA9EE,0x20200000
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.long 0x40020000,0xC90FDAA2,0x2168C235,0xA0800000
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.long 0x40020000,0xE231D5F6,0x6595DA7B,0x20B00000
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.long 0x40020000,0xFB53D14A,0xA9C2F2C2,0x9F800000
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.long 0x40030000,0x8A3AE64F,0x76F80584,0x21080000
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.long 0x40030000,0x96CBE3F9,0x990E91A8,0xA1600000
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.long 0x40030000,0xA35CE1A3,0xBB251DCB,0xA0900000
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.long 0x40030000,0xAFEDDF4D,0xDD3BA9EE,0x20A00000
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.long 0x40030000,0xBC7EDCF7,0xFF523611,0x21680000
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.long 0x40030000,0xC90FDAA2,0x2168C235,0xA1000000
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.long 0x40030000,0xD5A0D84C,0x437F4E58,0x1FC00000
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.long 0x40030000,0xE231D5F6,0x6595DA7B,0x21300000
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.long 0x40030000,0xEEC2D3A0,0x87AC669F,0xA1380000
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.long 0x40030000,0xFB53D14A,0xA9C2F2C2,0xA0000000
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.long 0x40040000,0x83F2677A,0x65ECBF73,0xA1C40000
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.long 0x40040000,0x8A3AE64F,0x76F80584,0x21880000
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.long 0x40040000,0x90836524,0x88034B96,0xA0B00000
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.long 0x40040000,0x96CBE3F9,0x990E91A8,0xA1E00000
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.long 0x40040000,0x9D1462CE,0xAA19D7B9,0x21580000
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.long 0x40040000,0xA35CE1A3,0xBB251DCB,0xA1100000
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.long 0x40040000,0xA9A56078,0xCC3063DD,0xA1FC0000
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.long 0x40040000,0xAFEDDF4D,0xDD3BA9EE,0x21200000
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.long 0x40040000,0xB6365E22,0xEE46F000,0xA1480000
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.long 0x40040000,0xBC7EDCF7,0xFF523611,0x21E80000
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.long 0x40040000,0xC2C75BCD,0x105D7C23,0x20D00000
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.long 0x40040000,0xC90FDAA2,0x2168C235,0xA1800000
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.set INARG,FP_SCR4
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.set TWOTO63,L_SCR1
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.set ENDFLAG,L_SCR2
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.set N,L_SCR3
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| xref t_frcinx
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|xref t_extdnrm
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.global stand
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stand:
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|--TAN(X) = X FOR DENORMALIZED X
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bra t_extdnrm
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.global stan
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stan:
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fmovex (%a0),%fp0 | ...LOAD INPUT
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movel (%a0),%d0
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movew 4(%a0),%d0
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andil #0x7FFFFFFF,%d0
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cmpil #0x3FD78000,%d0 | ...|X| >= 2**(-40)?
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bges TANOK1
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bra TANSM
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TANOK1:
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cmpil #0x4004BC7E,%d0 | ...|X| < 15 PI?
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blts TANMAIN
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bra REDUCEX
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TANMAIN:
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|--THIS IS THE USUAL CASE, |X| <= 15 PI.
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|--THE ARGUMENT REDUCTION IS DONE BY TABLE LOOK UP.
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fmovex %fp0,%fp1
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fmuld TWOBYPI,%fp1 | ...X*2/PI
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|--HIDE THE NEXT TWO INSTRUCTIONS
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leal PITBL+0x200,%a1 | ...TABLE OF N*PI/2, N = -32,...,32
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|--FP1 IS NOW READY
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fmovel %fp1,%d0 | ...CONVERT TO INTEGER
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asll #4,%d0
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addal %d0,%a1 | ...ADDRESS N*PIBY2 IN Y1, Y2
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fsubx (%a1)+,%fp0 | ...X-Y1
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|--HIDE THE NEXT ONE
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fsubs (%a1),%fp0 | ...FP0 IS R = (X-Y1)-Y2
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rorl #5,%d0
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andil #0x80000000,%d0 | ...D0 WAS ODD IFF D0 < 0
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TANCONT:
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cmpil #0,%d0
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blt NODD
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fmovex %fp0,%fp1
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fmulx %fp1,%fp1 | ...S = R*R
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fmoved TANQ4,%fp3
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fmoved TANP3,%fp2
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fmulx %fp1,%fp3 | ...SQ4
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fmulx %fp1,%fp2 | ...SP3
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faddd TANQ3,%fp3 | ...Q3+SQ4
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faddx TANP2,%fp2 | ...P2+SP3
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fmulx %fp1,%fp3 | ...S(Q3+SQ4)
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fmulx %fp1,%fp2 | ...S(P2+SP3)
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faddx TANQ2,%fp3 | ...Q2+S(Q3+SQ4)
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faddx TANP1,%fp2 | ...P1+S(P2+SP3)
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fmulx %fp1,%fp3 | ...S(Q2+S(Q3+SQ4))
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fmulx %fp1,%fp2 | ...S(P1+S(P2+SP3))
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faddx TANQ1,%fp3 | ...Q1+S(Q2+S(Q3+SQ4))
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fmulx %fp0,%fp2 | ...RS(P1+S(P2+SP3))
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fmulx %fp3,%fp1 | ...S(Q1+S(Q2+S(Q3+SQ4)))
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faddx %fp2,%fp0 | ...R+RS(P1+S(P2+SP3))
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fadds #0x3F800000,%fp1 | ...1+S(Q1+...)
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fmovel %d1,%fpcr |restore users exceptions
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fdivx %fp1,%fp0 |last inst - possible exception set
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bra t_frcinx
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NODD:
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fmovex %fp0,%fp1
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fmulx %fp0,%fp0 | ...S = R*R
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fmoved TANQ4,%fp3
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fmoved TANP3,%fp2
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fmulx %fp0,%fp3 | ...SQ4
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fmulx %fp0,%fp2 | ...SP3
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faddd TANQ3,%fp3 | ...Q3+SQ4
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faddx TANP2,%fp2 | ...P2+SP3
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fmulx %fp0,%fp3 | ...S(Q3+SQ4)
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fmulx %fp0,%fp2 | ...S(P2+SP3)
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faddx TANQ2,%fp3 | ...Q2+S(Q3+SQ4)
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faddx TANP1,%fp2 | ...P1+S(P2+SP3)
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fmulx %fp0,%fp3 | ...S(Q2+S(Q3+SQ4))
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fmulx %fp0,%fp2 | ...S(P1+S(P2+SP3))
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faddx TANQ1,%fp3 | ...Q1+S(Q2+S(Q3+SQ4))
|
| 275 |
|
|
fmulx %fp1,%fp2 | ...RS(P1+S(P2+SP3))
|
| 276 |
|
|
|
| 277 |
|
|
fmulx %fp3,%fp0 | ...S(Q1+S(Q2+S(Q3+SQ4)))
|
| 278 |
|
|
|
| 279 |
|
|
|
| 280 |
|
|
faddx %fp2,%fp1 | ...R+RS(P1+S(P2+SP3))
|
| 281 |
|
|
fadds #0x3F800000,%fp0 | ...1+S(Q1+...)
|
| 282 |
|
|
|
| 283 |
|
|
|
| 284 |
|
|
fmovex %fp1,-(%sp)
|
| 285 |
|
|
eoril #0x80000000,(%sp)
|
| 286 |
|
|
|
| 287 |
|
|
fmovel %d1,%fpcr |restore users exceptions
|
| 288 |
|
|
fdivx (%sp)+,%fp0 |last inst - possible exception set
|
| 289 |
|
|
|
| 290 |
|
|
bra t_frcinx
|
| 291 |
|
|
|
| 292 |
|
|
TANBORS:
|
| 293 |
|
|
|--IF |X| > 15PI, WE USE THE GENERAL ARGUMENT REDUCTION.
|
| 294 |
|
|
|--IF |X| < 2**(-40), RETURN X OR 1.
|
| 295 |
|
|
cmpil #0x3FFF8000,%d0
|
| 296 |
|
|
bgts REDUCEX
|
| 297 |
|
|
|
| 298 |
|
|
TANSM:
|
| 299 |
|
|
|
| 300 |
|
|
fmovex %fp0,-(%sp)
|
| 301 |
|
|
fmovel %d1,%fpcr |restore users exceptions
|
| 302 |
|
|
fmovex (%sp)+,%fp0 |last inst - possible exception set
|
| 303 |
|
|
|
| 304 |
|
|
bra t_frcinx
|
| 305 |
|
|
|
| 306 |
|
|
|
| 307 |
|
|
REDUCEX:
|
| 308 |
|
|
|--WHEN REDUCEX IS USED, THE CODE WILL INEVITABLY BE SLOW.
|
| 309 |
|
|
|--THIS REDUCTION METHOD, HOWEVER, IS MUCH FASTER THAN USING
|
| 310 |
|
|
|--THE REMAINDER INSTRUCTION WHICH IS NOW IN SOFTWARE.
|
| 311 |
|
|
|
| 312 |
|
|
fmovemx %fp2-%fp5,-(%a7) | ...save FP2 through FP5
|
| 313 |
|
|
movel %d2,-(%a7)
|
| 314 |
|
|
fmoves #0x00000000,%fp1
|
| 315 |
|
|
|
| 316 |
|
|
|--If compact form of abs(arg) in d0=$7ffeffff, argument is so large that
|
| 317 |
|
|
|--there is a danger of unwanted overflow in first LOOP iteration. In this
|
| 318 |
|
|
|--case, reduce argument by one remainder step to make subsequent reduction
|
| 319 |
|
|
|--safe.
|
| 320 |
|
|
cmpil #0x7ffeffff,%d0 |is argument dangerously large?
|
| 321 |
|
|
bnes LOOP
|
| 322 |
|
|
movel #0x7ffe0000,FP_SCR2(%a6) |yes
|
| 323 |
|
|
| ;create 2**16383*PI/2
|
| 324 |
|
|
movel #0xc90fdaa2,FP_SCR2+4(%a6)
|
| 325 |
|
|
clrl FP_SCR2+8(%a6)
|
| 326 |
|
|
ftstx %fp0 |test sign of argument
|
| 327 |
|
|
movel #0x7fdc0000,FP_SCR3(%a6) |create low half of 2**16383*
|
| 328 |
|
|
| ;PI/2 at FP_SCR3
|
| 329 |
|
|
movel #0x85a308d3,FP_SCR3+4(%a6)
|
| 330 |
|
|
clrl FP_SCR3+8(%a6)
|
| 331 |
|
|
fblt red_neg
|
| 332 |
|
|
orw #0x8000,FP_SCR2(%a6) |positive arg
|
| 333 |
|
|
orw #0x8000,FP_SCR3(%a6)
|
| 334 |
|
|
red_neg:
|
| 335 |
|
|
faddx FP_SCR2(%a6),%fp0 |high part of reduction is exact
|
| 336 |
|
|
fmovex %fp0,%fp1 |save high result in fp1
|
| 337 |
|
|
faddx FP_SCR3(%a6),%fp0 |low part of reduction
|
| 338 |
|
|
fsubx %fp0,%fp1 |determine low component of result
|
| 339 |
|
|
faddx FP_SCR3(%a6),%fp1 |fp0/fp1 are reduced argument.
|
| 340 |
|
|
|
| 341 |
|
|
|--ON ENTRY, FP0 IS X, ON RETURN, FP0 IS X REM PI/2, |X| <= PI/4.
|
| 342 |
|
|
|--integer quotient will be stored in N
|
| 343 |
|
|
|--Intermediate remainder is 66-bit long; (R,r) in (FP0,FP1)
|
| 344 |
|
|
|
| 345 |
|
|
LOOP:
|
| 346 |
|
|
fmovex %fp0,INARG(%a6) | ...+-2**K * F, 1 <= F < 2
|
| 347 |
|
|
movew INARG(%a6),%d0
|
| 348 |
|
|
movel %d0,%a1 | ...save a copy of D0
|
| 349 |
|
|
andil #0x00007FFF,%d0
|
| 350 |
|
|
subil #0x00003FFF,%d0 | ...D0 IS K
|
| 351 |
|
|
cmpil #28,%d0
|
| 352 |
|
|
bles LASTLOOP
|
| 353 |
|
|
CONTLOOP:
|
| 354 |
|
|
subil #27,%d0 | ...D0 IS L := K-27
|
| 355 |
|
|
movel #0,ENDFLAG(%a6)
|
| 356 |
|
|
bras WORK
|
| 357 |
|
|
LASTLOOP:
|
| 358 |
|
|
clrl %d0 | ...D0 IS L := 0
|
| 359 |
|
|
movel #1,ENDFLAG(%a6)
|
| 360 |
|
|
|
| 361 |
|
|
WORK:
|
| 362 |
|
|
|--FIND THE REMAINDER OF (R,r) W.R.T. 2**L * (PI/2). L IS SO CHOSEN
|
| 363 |
|
|
|--THAT INT( X * (2/PI) / 2**(L) ) < 2**29.
|
| 364 |
|
|
|
| 365 |
|
|
|--CREATE 2**(-L) * (2/PI), SIGN(INARG)*2**(63),
|
| 366 |
|
|
|--2**L * (PIby2_1), 2**L * (PIby2_2)
|
| 367 |
|
|
|
| 368 |
|
|
movel #0x00003FFE,%d2 | ...BIASED EXPO OF 2/PI
|
| 369 |
|
|
subl %d0,%d2 | ...BIASED EXPO OF 2**(-L)*(2/PI)
|
| 370 |
|
|
|
| 371 |
|
|
movel #0xA2F9836E,FP_SCR1+4(%a6)
|
| 372 |
|
|
movel #0x4E44152A,FP_SCR1+8(%a6)
|
| 373 |
|
|
movew %d2,FP_SCR1(%a6) | ...FP_SCR1 is 2**(-L)*(2/PI)
|
| 374 |
|
|
|
| 375 |
|
|
fmovex %fp0,%fp2
|
| 376 |
|
|
fmulx FP_SCR1(%a6),%fp2
|
| 377 |
|
|
|--WE MUST NOW FIND INT(FP2). SINCE WE NEED THIS VALUE IN
|
| 378 |
|
|
|--FLOATING POINT FORMAT, THE TWO FMOVE'S FMOVE.L FP <--> N
|
| 379 |
|
|
|--WILL BE TOO INEFFICIENT. THE WAY AROUND IT IS THAT
|
| 380 |
|
|
|--(SIGN(INARG)*2**63 + FP2) - SIGN(INARG)*2**63 WILL GIVE
|
| 381 |
|
|
|--US THE DESIRED VALUE IN FLOATING POINT.
|
| 382 |
|
|
|
| 383 |
|
|
|--HIDE SIX CYCLES OF INSTRUCTION
|
| 384 |
|
|
movel %a1,%d2
|
| 385 |
|
|
swap %d2
|
| 386 |
|
|
andil #0x80000000,%d2
|
| 387 |
|
|
oril #0x5F000000,%d2 | ...D2 IS SIGN(INARG)*2**63 IN SGL
|
| 388 |
|
|
movel %d2,TWOTO63(%a6)
|
| 389 |
|
|
|
| 390 |
|
|
movel %d0,%d2
|
| 391 |
|
|
addil #0x00003FFF,%d2 | ...BIASED EXPO OF 2**L * (PI/2)
|
| 392 |
|
|
|
| 393 |
|
|
|--FP2 IS READY
|
| 394 |
|
|
fadds TWOTO63(%a6),%fp2 | ...THE FRACTIONAL PART OF FP1 IS ROUNDED
|
| 395 |
|
|
|
| 396 |
|
|
|--HIDE 4 CYCLES OF INSTRUCTION; creating 2**(L)*Piby2_1 and 2**(L)*Piby2_2
|
| 397 |
|
|
movew %d2,FP_SCR2(%a6)
|
| 398 |
|
|
clrw FP_SCR2+2(%a6)
|
| 399 |
|
|
movel #0xC90FDAA2,FP_SCR2+4(%a6)
|
| 400 |
|
|
clrl FP_SCR2+8(%a6) | ...FP_SCR2 is 2**(L) * Piby2_1
|
| 401 |
|
|
|
| 402 |
|
|
|--FP2 IS READY
|
| 403 |
|
|
fsubs TWOTO63(%a6),%fp2 | ...FP2 is N
|
| 404 |
|
|
|
| 405 |
|
|
addil #0x00003FDD,%d0
|
| 406 |
|
|
movew %d0,FP_SCR3(%a6)
|
| 407 |
|
|
clrw FP_SCR3+2(%a6)
|
| 408 |
|
|
movel #0x85A308D3,FP_SCR3+4(%a6)
|
| 409 |
|
|
clrl FP_SCR3+8(%a6) | ...FP_SCR3 is 2**(L) * Piby2_2
|
| 410 |
|
|
|
| 411 |
|
|
movel ENDFLAG(%a6),%d0
|
| 412 |
|
|
|
| 413 |
|
|
|--We are now ready to perform (R+r) - N*P1 - N*P2, P1 = 2**(L) * Piby2_1 and
|
| 414 |
|
|
|--P2 = 2**(L) * Piby2_2
|
| 415 |
|
|
fmovex %fp2,%fp4
|
| 416 |
|
|
fmulx FP_SCR2(%a6),%fp4 | ...W = N*P1
|
| 417 |
|
|
fmovex %fp2,%fp5
|
| 418 |
|
|
fmulx FP_SCR3(%a6),%fp5 | ...w = N*P2
|
| 419 |
|
|
fmovex %fp4,%fp3
|
| 420 |
|
|
|--we want P+p = W+w but |p| <= half ulp of P
|
| 421 |
|
|
|--Then, we need to compute A := R-P and a := r-p
|
| 422 |
|
|
faddx %fp5,%fp3 | ...FP3 is P
|
| 423 |
|
|
fsubx %fp3,%fp4 | ...W-P
|
| 424 |
|
|
|
| 425 |
|
|
fsubx %fp3,%fp0 | ...FP0 is A := R - P
|
| 426 |
|
|
faddx %fp5,%fp4 | ...FP4 is p = (W-P)+w
|
| 427 |
|
|
|
| 428 |
|
|
fmovex %fp0,%fp3 | ...FP3 A
|
| 429 |
|
|
fsubx %fp4,%fp1 | ...FP1 is a := r - p
|
| 430 |
|
|
|
| 431 |
|
|
|--Now we need to normalize (A,a) to "new (R,r)" where R+r = A+a but
|
| 432 |
|
|
|--|r| <= half ulp of R.
|
| 433 |
|
|
faddx %fp1,%fp0 | ...FP0 is R := A+a
|
| 434 |
|
|
|--No need to calculate r if this is the last loop
|
| 435 |
|
|
cmpil #0,%d0
|
| 436 |
|
|
bgt RESTORE
|
| 437 |
|
|
|
| 438 |
|
|
|--Need to calculate r
|
| 439 |
|
|
fsubx %fp0,%fp3 | ...A-R
|
| 440 |
|
|
faddx %fp3,%fp1 | ...FP1 is r := (A-R)+a
|
| 441 |
|
|
bra LOOP
|
| 442 |
|
|
|
| 443 |
|
|
RESTORE:
|
| 444 |
|
|
fmovel %fp2,N(%a6)
|
| 445 |
|
|
movel (%a7)+,%d2
|
| 446 |
|
|
fmovemx (%a7)+,%fp2-%fp5
|
| 447 |
|
|
|
| 448 |
|
|
|
| 449 |
|
|
movel N(%a6),%d0
|
| 450 |
|
|
rorl #1,%d0
|
| 451 |
|
|
|
| 452 |
|
|
|
| 453 |
|
|
bra TANCONT
|
| 454 |
|
|
|
| 455 |
|
|
|end
|
