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/**************************** sumarray.as ***********************************
* Author: Agner Fog
* date created: 2018-02-24
* last modified: 2021-08-08
* Version: 1.11
* Project: ForwardCom example, assembly code
* Description: Calculates the sum of the numbers from 1 to 100
*
* This code will fill an array with the numbers from 1 to 100 and then
* calculate the sum. The purpose is to show how the variable-length vector
* instructions work.
* The expected result is the mean times the number: (1+100)*100/2 = 5050.
*
* Copyright 2018-2021 GNU General Public License http://www.gnu.org/licenses
*****************************************************************************/
%num = 100 // number of array elements
const section read ip // read-only data section
conclude: int8 "\nThe sum of numbers from 1 to %i is %i\n",0 // format string for printf
const end
bss section datap uninitialized // uninitialized read/write data section
int32 myarray[num] // array of 100 integers
int64 parlist[4] // parameter list for printf
bss end
code section execute align = 4 // code section
extern _printf: function // library function: formatted output to stdout
_main function public // program begins here
// Step 1: Fill myarray with numbers 1 .. 100
int64 r0 = num // = 100
int32 v1 = make_sequence(r0, 1) // will be (1, 2, 3, ...) up to as much as the maximum vector length allows, or 100
int32 r1 = get_num(v1) // number of elements in vector
int64 r2 = r1 - 1 // index to last element
int32 v2 = extract(v1, r2) // get last element and broadcast it
// A vector loop needs a pointer to the end of the array
int64 r2 = address [myarray+num*4] // address of the end of myarray
int64 r1 = num * 4 // total array size in bytes
// This loop will count down r1 with the maximum length until the array is filled
// The last iteration will automatically get fewer elements if the array size is not divisible by the maximum length
for (int32 v1 in [r2-r1]) {
int32 [r2-r1, length = r1] = v1 // put as many elements into the array as the maximum length permits
int32 v1 += v2 // add up the vector of sequential numbers
}
// Step 2: Calculate the sum of all elements in the array
int32 v0 = replace(v1, 0) // make a vector of all zeroes and same length
int64 r1 = num * 4 // total array size in bytes
// vector loop, counting down r1 with the maximum length until the array is filled
for (int32 v0 in [r2-r1]) {
int32 v0 += [r2-r1, length = r1] // add elements to vector
}
// Step 3: Calculate the horizontal sum of the elements in v0
int32 r1 = get_len(v0) // length of vector in bytes
// Round up the vector length to the nearest power of 2.
// The maximum vector length is known to be a power of 2,
// but the length may be 'num' elements, which is not a power of 2
int32 r1 = roundp2(r1, 1) // r1 is now a power of 2, not bigger than the maximum vector length
int32 v0 = set_len(v0, r1) // adjust vector length to nearest higher power of 2. Added elements will be zero
while (uint32+ r1 > 4) { // loop to calculate horizontal sum
uint32+ r1 >>= 1 // the vector length is halved
int32 v1 = shift_reduce (v0, r1) // get upper half of vector
// Add upper half and lower half
// The result vector has the length of the first operand, which will be halved each iteration
int32 v0 = v1 + v0
}
// The sum is now a scalar in v0
// Step 4: Write the result
int64 r0 = address([conclude]) // format string for printf
int64 r1 = address([parlist]) // parameter list
int32 [r1] = num // put number into parameter list
int32 [r1+8, scalar] = v0 // put result into parameter list
call _printf // printf("\nThe sum of numbers from 1 to %i is %i", num, v0)
// Return from main
int64 r0 = 0 // program return value
return // return from main
_main end
code end
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