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[/] [open8_urisc/] [trunk/] [VHDL/] [intdiv.vhd] - Rev 329

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-- Copyright (c)2023 Jeremy Seth Henry
-- All rights reserved.
--
-- Redistribution and use in source and binary forms, with or without
-- modification, are permitted provided that the following conditions are met:
--     * Redistributions of source code must retain the above copyright
--       notice, this list of conditions and the following disclaimer.
--     * Redistributions in binary form must reproduce the above copyright
--       notice, this list of conditions and the following disclaimer in the
--       documentation and/or other materials provided with the distribution,
--       where applicable (as part of a user interface, debugging port, etc.)
--
-- THIS SOFTWARE IS PROVIDED BY JEREMY SETH HENRY ``AS IS'' AND ANY
-- EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED
-- WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE
-- DISCLAIMED. IN NO EVENT SHALL JEREMY SETH HENRY BE LIABLE FOR ANY
-- DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES
-- (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES;
-- LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND
-- ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
-- (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF
-- THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
--
-- VHDL units : intdiv
-- Description: Performs an integer division operation using a restoring
--               algorithm that produces both a quotient and a remainder.
--              Note that the Dividend and Divisor have the same bit width.
--
-- Algorithm:
--  1: Initialize registers (Q = Dividend, M = Divisor, R = 0, N = number of bits in dividend)
--  2: Shift R & Q (RQ) left by 1
--  3: Calculate difference R = R - M
--  4: Check the sign of the result.
--     If the MSB of RQ (R) is '0' (R >= M), then set the LSB of RQ (Q) to a '1'
--     If the MSB of RQ (R) is '1' (M > R) then restore R and set the LSB of Q to '0'
--  5: Loop to step 2 while N < Div_Width (Dividend Width)
--  6: Assign Q to Quotient and R to Remainder
--
-- Revision History
-- Author          Date     Change
------------------ -------- ---------------------------------------------------
-- Seth Henry      04/10/23 Initial Design
 
library ieee;
use ieee.std_logic_1164.all;
use ieee.std_logic_unsigned.all;
 
entity intdiv is
generic(
  Div_Width             : integer   := 16;
  Reset_Level           : std_logic := '0'
);
port(
  Clock                 : in  std_logic;
  Reset                 : in  std_logic;
  --
  Enable                : in  std_logic;
  Busy                  : out std_logic;
  --
  Dividend              : in  std_logic_vector(Div_Width - 1 downto 0);
  Divisor               : in  std_logic_vector(Div_Width - 1 downto 0);
  Quotient              : out std_logic_vector(Div_Width - 1 downto 0);
  Remainder             : out std_logic_vector(Div_Width - 1 downto 0)
);
end entity;
 
architecture behave of intdiv is
 
  -- RQ combines R & Q into a single register
  signal RQ             : std_logic_vector(Div_Width*2-1 downto 0) :=
                           (others => '0');
 
  alias  R              is RQ(Div_Width*2-1 downto Div_Width);
  alias  Q              is RQ(Div_Width-1 downto 0);
 
  -- Dividend is assumed to be the same width as the Divisor
  signal M              : std_logic_vector(Div_Width - 1 downto 0) :=
                           (others => '0');
 
  -- Difference result should be 1 bit larger than the Dividend to allow for
  --  a sign bit
  signal D              : std_logic_vector(Div_Width downto 0) :=
                           (others => '0');
 
  alias  S              is D(Div_Width);
 
  constant LZ           : std_logic_vector(Div_Width - 1 downto 0) :=
                            (others => '0');
 
  signal N              : integer range 0 to Div_Width := 0;
 
begin
 
  Quotient              <= Q;
  Remainder             <= R;
 
  -- This statement combines the left shift logic with the subtraction.
  -- Leading '0's are used to force both arguments to be positive.
  D                     <= ('0' & RQ(Div_Width*2-2 downto Div_Width-1)) -
                           ('0' & M);
 
  Divide_proc: process( Clock, Reset )
  begin
    if( Reset = Reset_Level )then
      RQ                <= (others => '0');
      M                 <= (others => '0');
      N                 <= 0;
      Busy              <= '0';
    elsif( rising_edge(Clock) )then
      Busy              <= '0';
 
      if( Enable = '1' )then
        Busy            <= '1';
        N               <= Div_Width;
        RQ              <= LZ & Dividend;
        M               <= Divisor;
      end if;
 
      if( N > 0 )then
        Busy            <= '1';
        N               <= N - 1;
        -- Leave R set to R-M and set Q[0] to '1'
        RQ              <= D(Div_Width-1 downto 0) &  -- New R
                           RQ(Div_Width-2 downto 0) & -- Q<<1
                           '1';                       -- Q(0) = '1'
        if( S = '1' )then
          -- Restore R and set Q[0] to '0'
          RQ            <= RQ(Div_Width*2-2 downto 0) & '0';
        end if;
      end if;
    end if;
  end process;
 
end architecture;
 

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