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// Copyright 2010 The Go Authors. All rights reserved.// Use of this source code is governed by a BSD-style// license that can be found in the LICENSE file.package math/*Bessel function of the first and second kinds of order n.*/// The original C code and the long comment below are// from FreeBSD's /usr/src/lib/msun/src/e_jn.c and// came with this notice. The go code is a simplified// version of the original C.//// ====================================================// Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.//// Developed at SunPro, a Sun Microsystems, Inc. business.// Permission to use, copy, modify, and distribute this// software is freely granted, provided that this notice// is preserved.// ====================================================//// __ieee754_jn(n, x), __ieee754_yn(n, x)// floating point Bessel's function of the 1st and 2nd kind// of order n//// Special cases:// y0(0)=y1(0)=yn(n,0) = -inf with division by zero signal;// y0(-ve)=y1(-ve)=yn(n,-ve) are NaN with invalid signal.// Note 2. About jn(n,x), yn(n,x)// For n=0, j0(x) is called,// for n=1, j1(x) is called,// for n<x, forward recursion is used starting// from values of j0(x) and j1(x).// for n>x, a continued fraction approximation to// j(n,x)/j(n-1,x) is evaluated and then backward// recursion is used starting from a supposed value// for j(n,x). The resulting value of j(0,x) is// compared with the actual value to correct the// supposed value of j(n,x).//// yn(n,x) is similar in all respects, except// that forward recursion is used for all// values of n>1.// Jn returns the order-n Bessel function of the first kind.//// Special cases are:// Jn(n, ±Inf) = 0// Jn(n, NaN) = NaNfunc Jn(n int, x float64) float64 {const (TwoM29 = 1.0 / (1 << 29) // 2**-29 0x3e10000000000000Two302 = 1 << 302 // 2**302 0x52D0000000000000)// special casesswitch {case IsNaN(x):return xcase IsInf(x, 0):return 0}// J(-n, x) = (-1)**n * J(n, x), J(n, -x) = (-1)**n * J(n, x)// Thus, J(-n, x) = J(n, -x)if n == 0 {return J0(x)}if x == 0 {return 0}if n < 0 {n, x = -n, -x}if n == 1 {return J1(x)}sign := falseif x < 0 {x = -xif n&1 == 1 {sign = true // odd n and negative x}}var b float64if float64(n) <= x {// Safe to use J(n+1,x)=2n/x *J(n,x)-J(n-1,x)if x >= Two302 { // x > 2**302// (x >> n**2)// Jn(x) = cos(x-(2n+1)*pi/4)*sqrt(2/x*pi)// Yn(x) = sin(x-(2n+1)*pi/4)*sqrt(2/x*pi)// Let s=sin(x), c=cos(x),// xn=x-(2n+1)*pi/4, sqt2 = sqrt(2),then//// n sin(xn)*sqt2 cos(xn)*sqt2// ----------------------------------// 0 s-c c+s// 1 -s-c -c+s// 2 -s+c -c-s// 3 s+c c-svar temp float64switch n & 3 {case 0:temp = Cos(x) + Sin(x)case 1:temp = -Cos(x) + Sin(x)case 2:temp = -Cos(x) - Sin(x)case 3:temp = Cos(x) - Sin(x)}b = (1 / SqrtPi) * temp / Sqrt(x)} else {b = J1(x)for i, a := 1, J0(x); i < n; i++ {a, b = b, b*(float64(i+i)/x)-a // avoid underflow}}} else {if x < TwoM29 { // x < 2**-29// x is tiny, return the first Taylor expansion of J(n,x)// J(n,x) = 1/n!*(x/2)**n - ...if n > 33 { // underflowb = 0} else {temp := x * 0.5b = tempa := 1.0for i := 2; i <= n; i++ {a *= float64(i) // a = n!b *= temp // b = (x/2)**n}b /= a}} else {// use backward recurrence// x x**2 x**2// J(n,x)/J(n-1,x) = ---- ------ ------ .....// 2n - 2(n+1) - 2(n+2)//// 1 1 1// (for large x) = ---- ------ ------ .....// 2n 2(n+1) 2(n+2)// -- - ------ - ------ -// x x x//// Let w = 2n/x and h=2/x, then the above quotient// is equal to the continued fraction:// 1// = -----------------------// 1// w - -----------------// 1// w+h - ---------// w+2h - ...//// To determine how many terms needed, let// Q(0) = w, Q(1) = w(w+h) - 1,// Q(k) = (w+k*h)*Q(k-1) - Q(k-2),// When Q(k) > 1e4 good for single// When Q(k) > 1e9 good for double// When Q(k) > 1e17 good for quadruple// determine kw := float64(n+n) / xh := 2 / xq0 := wz := w + hq1 := w*z - 1k := 1for q1 < 1e9 {k += 1z += hq0, q1 = q1, z*q1-q0}m := n + nt := 0.0for i := 2 * (n + k); i >= m; i -= 2 {t = 1 / (float64(i)/x - t)}a := tb = 1// estimate log((2/x)**n*n!) = n*log(2/x)+n*ln(n)// Hence, if n*(log(2n/x)) > ...// single 8.8722839355e+01// double 7.09782712893383973096e+02// long double 1.1356523406294143949491931077970765006170e+04// then recurrent value may overflow and the result is// likely underflow to zerotmp := float64(n)v := 2 / xtmp = tmp * Log(Abs(v*tmp))if tmp < 7.09782712893383973096e+02 {for i := n - 1; i > 0; i-- {di := float64(i + i)a, b = b, b*di/x-adi -= 2}} else {for i := n - 1; i > 0; i-- {di := float64(i + i)a, b = b, b*di/x-adi -= 2// scale b to avoid spurious overflowif b > 1e100 {a /= bt /= bb = 1}}}b = t * J0(x) / b}}if sign {return -b}return b}// Yn returns the order-n Bessel function of the second kind.//// Special cases are:// Yn(n, +Inf) = 0// Yn(n > 0, 0) = -Inf// Yn(n < 0, 0) = +Inf if n is odd, -Inf if n is even// Y1(n, x < 0) = NaN// Y1(n, NaN) = NaNfunc Yn(n int, x float64) float64 {const Two302 = 1 << 302 // 2**302 0x52D0000000000000// special casesswitch {case x < 0 || IsNaN(x):return NaN()case IsInf(x, 1):return 0}if n == 0 {return Y0(x)}if x == 0 {if n < 0 && n&1 == 1 {return Inf(1)}return Inf(-1)}sign := falseif n < 0 {n = -nif n&1 == 1 {sign = true // sign true if n < 0 && |n| odd}}if n == 1 {if sign {return -Y1(x)}return Y1(x)}var b float64if x >= Two302 { // x > 2**302// (x >> n**2)// Jn(x) = cos(x-(2n+1)*pi/4)*sqrt(2/x*pi)// Yn(x) = sin(x-(2n+1)*pi/4)*sqrt(2/x*pi)// Let s=sin(x), c=cos(x),// xn=x-(2n+1)*pi/4, sqt2 = sqrt(2),then//// n sin(xn)*sqt2 cos(xn)*sqt2// ----------------------------------// 0 s-c c+s// 1 -s-c -c+s// 2 -s+c -c-s// 3 s+c c-svar temp float64switch n & 3 {case 0:temp = Sin(x) - Cos(x)case 1:temp = -Sin(x) - Cos(x)case 2:temp = -Sin(x) + Cos(x)case 3:temp = Sin(x) + Cos(x)}b = (1 / SqrtPi) * temp / Sqrt(x)} else {a := Y0(x)b = Y1(x)// quit if b is -inffor i := 1; i < n && !IsInf(b, -1); i++ {a, b = b, (float64(i+i)/x)*b-a}}if sign {return -b}return b}
