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[/] [openrisc/] [trunk/] [gnu-old/] [binutils-2.18.50/] [intl/] [plural.y] - Rev 816

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%{
/* Expression parsing for plural form selection.
   Copyright (C) 2000, 2001 Free Software Foundation, Inc.
   Written by Ulrich Drepper <drepper@cygnus.com>, 2000.

   This program is free software; you can redistribute it and/or modify it
   under the terms of the GNU Library General Public License as published
   by the Free Software Foundation; either version 2, or (at your option)
   any later version.

   This program is distributed in the hope that it will be useful,
   but WITHOUT ANY WARRANTY; without even the implied warranty of
   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
   Library General Public License for more details.

   You should have received a copy of the GNU Library General Public
   License along with this program; if not, write to the Free Software
   Foundation, Inc., 51 Franklin Street - Fifth Floor, Boston, MA 02110-1301,
   USA.  */

/* The bison generated parser uses alloca.  AIX 3 forces us to put this
   declaration at the beginning of the file.  The declaration in bison's
   skeleton file comes too late.  This must come before <config.h>
   because <config.h> may include arbitrary system headers.  */
#if defined _AIX && !defined __GNUC__
 #pragma alloca
#endif

#ifdef HAVE_CONFIG_H
# include <config.h>
#endif

#include <stddef.h>
#include <stdlib.h>
#include "plural-exp.h"

/* The main function generated by the parser is called __gettextparse,
   but we want it to be called PLURAL_PARSE.  */
#ifndef _LIBC
# define __gettextparse PLURAL_PARSE
#endif

#define YYLEX_PARAM     &((struct parse_args *) arg)->cp
#define YYPARSE_PARAM   arg
%}
%pure_parser
%expect 7

%union {
  unsigned long int num;
  enum operator op;
  struct expression *exp;
}

%{
/* Prototypes for local functions.  */
static struct expression *new_exp PARAMS ((int nargs, enum operator op,
                                           struct expression * const *args));
static inline struct expression *new_exp_0 PARAMS ((enum operator op));
static inline struct expression *new_exp_1 PARAMS ((enum operator op,
                                                   struct expression *right));
static struct expression *new_exp_2 PARAMS ((enum operator op,
                                             struct expression *left,
                                             struct expression *right));
static inline struct expression *new_exp_3 PARAMS ((enum operator op,
                                                   struct expression *bexp,
                                                   struct expression *tbranch,
                                                   struct expression *fbranch));
static int yylex PARAMS ((YYSTYPE *lval, const char **pexp));
static void yyerror PARAMS ((const char *str));

/* Allocation of expressions.  */

static struct expression *
new_exp (nargs, op, args)
     int nargs;
     enum operator op;
     struct expression * const *args;
{
  int i;
  struct expression *newp;

  /* If any of the argument could not be malloc'ed, just return NULL.  */
  for (i = nargs - 1; i >= 0; i--)
    if (args[i] == NULL)
      goto fail;

  /* Allocate a new expression.  */
  newp = (struct expression *) malloc (sizeof (*newp));
  if (newp != NULL)
    {
      newp->nargs = nargs;
      newp->operation = op;
      for (i = nargs - 1; i >= 0; i--)
        newp->val.args[i] = args[i];
      return newp;
    }

 fail:
  for (i = nargs - 1; i >= 0; i--)
    FREE_EXPRESSION (args[i]);

  return NULL;
}

static inline struct expression *
new_exp_0 (op)
     enum operator op;
{
  return new_exp (0, op, NULL);
}

static inline struct expression *
new_exp_1 (op, right)
     enum operator op;
     struct expression *right;
{
  struct expression *args[1];

  args[0] = right;
  return new_exp (1, op, args);
}

static struct expression *
new_exp_2 (op, left, right)
     enum operator op;
     struct expression *left;
     struct expression *right;
{
  struct expression *args[2];

  args[0] = left;
  args[1] = right;
  return new_exp (2, op, args);
}

static inline struct expression *
new_exp_3 (op, bexp, tbranch, fbranch)
     enum operator op;
     struct expression *bexp;
     struct expression *tbranch;
     struct expression *fbranch;
{
  struct expression *args[3];

  args[0] = bexp;
  args[1] = tbranch;
  args[2] = fbranch;
  return new_exp (3, op, args);
}

%}

/* This declares that all operators have the same associativity and the
   precedence order as in C.  See [Harbison, Steele: C, A Reference Manual].
   There is no unary minus and no bitwise operators.
   Operators with the same syntactic behaviour have been merged into a single
   token, to save space in the array generated by bison.  */
%right '?'              /*   ?          */
%left '|'               /*   ||         */
%left '&'               /*   &&         */
%left EQUOP2            /*   == !=      */
%left CMPOP2            /*   < > <= >=  */
%left ADDOP2            /*   + -        */
%left MULOP2            /*   * / %      */
%right '!'              /*   !          */

%token <op> EQUOP2 CMPOP2 ADDOP2 MULOP2
%token <num> NUMBER
%type <exp> exp

%%

start:    exp
          {
            if ($1 == NULL)
              YYABORT;
            ((struct parse_args *) arg)->res = $1;
          }
        ;

exp:      exp '?' exp ':' exp
          {
            $$ = new_exp_3 (qmop, $1, $3, $5);
          }
        | exp '|' exp
          {
            $$ = new_exp_2 (lor, $1, $3);
          }
        | exp '&' exp
          {
            $$ = new_exp_2 (land, $1, $3);
          }
        | exp EQUOP2 exp
          {
            $$ = new_exp_2 ($2, $1, $3);
          }
        | exp CMPOP2 exp
          {
            $$ = new_exp_2 ($2, $1, $3);
          }
        | exp ADDOP2 exp
          {
            $$ = new_exp_2 ($2, $1, $3);
          }
        | exp MULOP2 exp
          {
            $$ = new_exp_2 ($2, $1, $3);
          }
        | '!' exp
          {
            $$ = new_exp_1 (lnot, $2);
          }
        | 'n'
          {
            $$ = new_exp_0 (var);
          }
        | NUMBER
          {
            if (($$ = new_exp_0 (num)) != NULL)
              $$->val.num = $1;
          }
        | '(' exp ')'
          {
            $$ = $2;
          }
        ;

%%

void
internal_function
FREE_EXPRESSION (exp)
     struct expression *exp;
{
  if (exp == NULL)
    return;

  /* Handle the recursive case.  */
  switch (exp->nargs)
    {
    case 3:
      FREE_EXPRESSION (exp->val.args[2]);
      /* FALLTHROUGH */
    case 2:
      FREE_EXPRESSION (exp->val.args[1]);
      /* FALLTHROUGH */
    case 1:
      FREE_EXPRESSION (exp->val.args[0]);
      /* FALLTHROUGH */
    default:
      break;
    }

  free (exp);
}


static int
yylex (lval, pexp)
     YYSTYPE *lval;
     const char **pexp;
{
  const char *exp = *pexp;
  int result;

  while (1)
    {
      if (exp[0] == '\0')
        {
          *pexp = exp;
          return YYEOF;
        }

      if (exp[0] != ' ' && exp[0] != '\t')
        break;

      ++exp;
    }

  result = *exp++;
  switch (result)
    {
    case '0': case '1': case '2': case '3': case '4':
    case '5': case '6': case '7': case '8': case '9':
      {
        unsigned long int n = result - '0';
        while (exp[0] >= '0' && exp[0] <= '9')
          {
            n *= 10;
            n += exp[0] - '0';
            ++exp;
          }
        lval->num = n;
        result = NUMBER;
      }
      break;

    case '=':
      if (exp[0] == '=')
        {
          ++exp;
          lval->op = equal;
          result = EQUOP2;
        }
      else
        result = YYERRCODE;
      break;

    case '!':
      if (exp[0] == '=')
        {
          ++exp;
          lval->op = not_equal;
          result = EQUOP2;
        }
      break;

    case '&':
    case '|':
      if (exp[0] == result)
        ++exp;
      else
        result = YYERRCODE;
      break;

    case '<':
      if (exp[0] == '=')
        {
          ++exp;
          lval->op = less_or_equal;
        }
      else
        lval->op = less_than;
      result = CMPOP2;
      break;

    case '>':
      if (exp[0] == '=')
        {
          ++exp;
          lval->op = greater_or_equal;
        }
      else
        lval->op = greater_than;
      result = CMPOP2;
      break;

    case '*':
      lval->op = mult;
      result = MULOP2;
      break;

    case '/':
      lval->op = divide;
      result = MULOP2;
      break;

    case '%':
      lval->op = module;
      result = MULOP2;
      break;

    case '+':
      lval->op = plus;
      result = ADDOP2;
      break;

    case '-':
      lval->op = minus;
      result = ADDOP2;
      break;

    case 'n':
    case '?':
    case ':':
    case '(':
    case ')':
      /* Nothing, just return the character.  */
      break;

    case ';':
    case '\n':
    case '\0':
      /* Be safe and let the user call this function again.  */
      --exp;
      result = YYEOF;
      break;

    default:
      result = YYERRCODE;
#if YYDEBUG != 0
      --exp;
#endif
      break;
    }

  *pexp = exp;

  return result;
}


static void
yyerror (str)
     const char *str;
{
  /* Do nothing.  We don't print error messages here.  */
}

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