URL
https://opencores.org/ocsvn/openrisc_2011-10-31/openrisc_2011-10-31/trunk
Subversion Repositories openrisc_2011-10-31
[/] [openrisc/] [trunk/] [gnu-src/] [newlib-1.17.0/] [newlib/] [libc/] [stdlib/] [lldiv.c] - Rev 430
Go to most recent revision | Compare with Previous | Blame | View Log
/* FUNCTION <<lldiv>>---divide two long long integers INDEX lldiv ANSI_SYNOPSIS #include <stdlib.h> lldiv_t lldiv(long long <[n]>, long long <[d]>); TRAD_SYNOPSIS #include <stdlib.h> lldiv_t lldiv(<[n]>, <[d]>) long long <[n]>, <[d]>; DESCRIPTION Divide @tex $n/d$, @end tex @ifnottex <[n]>/<[d]>, @end ifnottex returning quotient and remainder as two long long integers in a structure <<lldiv_t>>. RETURNS The result is represented with the structure . typedef struct . { . long long quot; . long long rem; . } lldiv_t; where the <<quot>> field represents the quotient, and <<rem>> the remainder. For nonzero <[d]>, if `<<<[r]> = ldiv(<[n]>,<[d]>);>>' then <[n]> equals `<<<[r]>.rem + <[d]>*<[r]>.quot>>'. To divide <<long>> rather than <<long long>> values, use the similar function <<ldiv>>. PORTABILITY <<lldiv>> is ISO 9899 (C99) compatable. No supporting OS subroutines are required. */ /*- * Copyright (c) 2001 Mike Barcroft <mike@FreeBSD.org> * All rights reserved. * * Redistribution and use in source and binary forms, with or without * modification, are permitted provided that the following conditions * are met: * 1. Redistributions of source code must retain the above copyright * notice, this list of conditions and the following disclaimer. * 2. Redistributions in binary form must reproduce the above copyright * notice, this list of conditions and the following disclaimer in the * documentation and/or other materials provided with the distribution. * * THIS SOFTWARE IS PROVIDED BY THE AUTHOR AND CONTRIBUTORS ``AS IS'' AND * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE * ARE DISCLAIMED. IN NO EVENT SHALL THE AUTHOR OR CONTRIBUTORS BE LIABLE * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF * SUCH DAMAGE. */ #include <stdlib.h> /* * The ANSI standard says that |r.quot| <= |n/d|, where * n/d is to be computed in infinite precision. In other * words, we should always truncate the quotient towards * 0, never -infinity. * * Machine division and remainer may work either way when * one or both of n or d is negative. If only one is * negative and r.quot has been truncated towards -inf, * r.rem will have the same sign as denom and the opposite * sign of num; if both are negative and r.quot has been * truncated towards -inf, r.rem will be positive (will * have the opposite sign of num). These are considered * `wrong'. * * If both are num and denom are positive, r will always * be positive. * * This all boils down to: * if num >= 0, but r.rem < 0, we got the wrong answer. * In that case, to get the right answer, add 1 to r.quot and * subtract denom from r.rem. */ lldiv_t _DEFUN (lldiv, (number, denom), long long numer _AND long long denom) { lldiv_t retval; retval.quot = numer / denom; retval.rem = numer % denom; if (numer >= 0 && retval.rem < 0) { retval.quot++; retval.rem -= denom; } return (retval); }
Go to most recent revision | Compare with Previous | Blame | View Log