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[/] [scarts/] [trunk/] [toolchain/] [scarts-gcc/] [gcc-4.1.1/] [gcc/] [testsuite/] [gfortran.dg/] [null_1.f90] - Rev 12
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! { dg-do compile }
! PR fortran/20858
! If we have "x = null(i)", then "null()" acquires the type, kind type,
! and rank of i and these need to match those of x.
program null_1
integer, parameter :: sp = kind(1.e0), dp = kind(1.d0)
integer, pointer :: i => null()
real(sp), pointer :: x => null()
real(dp), pointer :: y => null()
real(sp), pointer :: z(:) => null()
x => null(i) ! { dg-error "types in pointer assignment" }
x => null(y) ! { dg-error "types in pointer assignment" }
z => null(i) ! { dg-error "types in pointer assignment" }
z => null(y) ! { dg-error "types in pointer assignment" }
x => null(z) ! { dg-error "ranks in pointer assignment" }
z => null(x) ! { dg-error "ranks in pointer assignment" }
z => null(z)
nullify(i, x, y, z)
end program null_1