1/1 
|
Implementaion of log func in verilog
by niladri.s.debnath on Mar 9, 2012 |
niladri.s.debnath
Posts: 1 Joined: Jun 23, 2011 Last seen: Mar 9, 2012 |
||
|
Hello everybody I want to implement log function in verilog can somebody give me some idea ????
|
|||
|
RE: Implementaion of log func in verilog
by motilito on Mar 9, 2012 |
motilito
Posts: 17 Joined: Jun 10, 2008 Last seen: Nov 17, 2025 |
||
|
Hi,
There is a nice trick to implement a the log function using RTL. if you take any binary value value you can define it using a simple floating point like manner: value=2^(exponent)*mantissa The "exponent" can be easily found by looking for the highest bit. the "mantissa" are the bits following the highest bit. calculate the log function of the above: log(value)=exponent*log(2) + log(mantissa) The "log(mantissa)" value is best calculated using a simple look up table. the desired result resolution defines the LUT size and thus the number of mantissa bits. Now, if you want to calculate the log base 2 of the value then ... simple solution. I bet you are more interested in calculating something like log10(value). The math is simple. Have fun, Moti |
|||
|
RE: Implementaion of log func in verilog
by jeremybennett on Mar 10, 2012 |
jeremybennett
Posts: 815 Joined: May 29, 2008 Last seen: Jun 13, 2019 |
||
|
You can find more details of the algorithms described by Moti on the University of Kentucky Aggregate Magic Algorithms page. HTH Jeremy
-- |
|||
1/1